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Vedmedyk [2.9K]
1 year ago
7

which two gases in earths atmosphere are believed by scientists to be greenhouse gases that are major contributors to global war

ming
Physics
1 answer:
Olenka [21]1 year ago
4 0
Nitrogen and carbon dioxide??
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A small cork with an excess charge of +6.0µC is placed 0.12 m from another cork, which carries a charge of -4.3µC.
Volgvan

A) 16.1 N

The magnitude of the electric force between the corks is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q_1 = 6.0 \mu C=6.0 \cdot 10^{-6} C is the magnitude of the charge on the first cork

q_2 = 4.3 \mu C = 4.3 \cdot 10^{-6}C is the magnitude of the charge of the second cork

r = 0.12 m is the separation between the two corks

Substituting numbers into the formula, we find

F=(9\cdot 10^9 N m^2 C^{-2} )\frac{(6.0\cdot 10^{-6}C)(4.3\cdot 10^{-6} C)}{(0.12 m)^2}=16.1 N

B) Attractive

According to Coulomb's law, the direction of the electric force between two charged objects depends on the sign of the charge of the two objects.

In particular, we have:

- if the two objects have charges with same sign (e.g. positive-positive or negative-negative), the force is repulsive

- if the two objects have charges with opposite sign (e.g. positive-negative), the force is attractive

In this problem, we have

Cork 1 has a positive charge

Cork 2 has a negative charge

So, the force between them is attractive.

C) 2.69\cdot 10^{13}

The net charge of the negative cork is

q_2 = -4.3 \cdot 10^{-6}C

We know that the charge of a single electron is

e=-1.6\cdot 10^{-19}C

The net charge on the negative cork is due to the presence of N excess electrons, so we can write

q_2 = Ne

and solving for N, we find the number of excess electrons:

N=\frac{q_2}{e}=\frac{-4.3\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=2.69\cdot 10^{13}

D) 3.75\cdot 10^{13}

The net charge on the positive cork is

q_1 = +6.0\cdot 10^{-6}C

We know that the charge of a single electron is

e=-1.6\cdot 10^{-19}C

The net charge on the positive cork is due to the "absence" of N excess electrons, so we can write

q_1 = -Ne

and solving for N, we find the number of electrons lost by the cork:

N=-\frac{q_1}{e}=-\frac{+6.0\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=3.75\cdot 10^{13}

6 0
3 years ago
A certain part of a computer chip has a length of 1.5 micrometers. How many meters is this ?
Alchen [17]

When you're working with units of measure, "micro" almost always means "millionth", or 1 x 10⁻⁶ .  And that's exactly the case in this example.

"1.5 micrometer" = 1.5 millionths of a meter, or <em>1.5 x  10⁻⁶ meter.</em>

4 0
3 years ago
A double slit experiment is conducted in air using a laser at 532nm and a slit separation of 20um. What happens to the fringe sp
Reika [66]

Answer:

Option B - The fringe spacing will increase

Explanation:

We are given;

Wavelength; λ = 532nm

slit separation; d = 20um

For double-slit experiment, the fringe width is given by the expression;

β = λD/d

Where;

β is the fringe width

λ is the wavelength

D is the distance between the screen and the slit

d is the slit separation

Now, when immersed in water, the slit separation distance will decrease.

Now, from the fringe width equation, when "d" decreases, it means that we will have a bigger value of fringe width.

Thus, as slit separation decreases, the fringe width increases.

3 0
3 years ago
Sorry about last time sorry the question is
Ivanshal [37]

Explanation:

It will increase as according to the Newton gravitational law the force of attraction is directly proportional to the product of the masses and inversely proportional to the square of the distance separating them

In case of atoms it will increase the decrease

8 0
3 years ago
A runner starts from rest, runs for 30
aleksklad [387]

Answer:

u=0

t=30s

a=2m/s²

v=?

v= u+at

= 0+(30)(2)

= 60m/s

6 0
3 years ago
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