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Vedmedyk [2.9K]
1 year ago
7

which two gases in earths atmosphere are believed by scientists to be greenhouse gases that are major contributors to global war

ming
Physics
1 answer:
Olenka [21]1 year ago
4 0
Nitrogen and carbon dioxide??
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Which of the following is NOT a fundamental S.I unit? A. Meter B. Ampere C. Kelvin D. Radian
Llana [10]

Explanation:

D . Radian is not a fundamental S.I unit

7 0
3 years ago
All of the following except ______ were part of RCA. A. Westinghouse B. Columbia Broadcasting System C. United Fruit Company D.
PSYCHO15rus [73]

Answer:

Columbia broadcasting system was never been a part of RCA corporation. The other companies Westinghouse, united fruit company and general electric were remain as part of RCA.

Explanation:

7 0
3 years ago
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 4.50 m above
Virty [35]

8.98×10^6\:\text{m}

Explanation:

First we need to find the acceleration due to gravity on the planet. The wrench took 0.809 s to fall from a height of 4.50 m so we can use the equation

y = -\frac{1}{2}gt^2

Solving for g, we get

g = -\dfrac{2y}{t^2} = -\dfrac{2(-4.50\:\text{m})}{(0.809\:\text{s})} = 13.8\:\text{m/s}^2

Recall that the acceleration due to gravity on a planet's surface can be written as

g = G\dfrac{M_p}{R_p^2}

We can express the mass of the planet M_p in terms of its density \rho as follows:

M_p = \rho \left(\dfrac{4\pi}{3}R_p^3\right) = \dfrac{4\pi}{3}\rho R_p^3

The expression for g then becomes

g = \dfrac{G}{R_p^2} \left(\dfrac{4\pi}{3}\rho R_p^3\right) = \dfrac{4\pi G}{3}\rho R_p

Solving for R_p, we get

R_p = \dfrac{3g}{4\pi G\rho}

\:\:\:\:\:\:\:= \left[\dfrac{3(13.8\:\text{m/s}^2)}{4\pi (6.674×10^{-11}\:\text{Nm}^2\text{/kg}^2)(5500\:\text{kg/m}^3)}\right]

\:\:\:\:\:\:\:= 8.98×10^6\:\text{m}

3 0
3 years ago
2. An optical fibre is 1200km long and it takes light 0.006s to travel from one end to the other. Calculate the speed of light i
natita [175]
The average speed <em>appears to be</em> (distance) / (time) =

(length of the cable) / (time from when a pulse goes in until it comes out the other end) .

That's  1,200,000 meters/ 0.006 second  =  2 x 10^8 = <em>2 hundred million m/sec</em>

That figure is about 66.7% of the speed of light in vacuum.

The reason I went through all of this detail was to point out that this is
NOT necessarily the speed of light in this glass, for two reasons.

1).  The path of light through an optical fiber is not straight down the middle.  In the original fibers of 20 or 30 years ago, the light bounced back and forth off the inside walls of the fiber, and zig-zagged its way along the length.  In current modern fibers, it still zig-zags, but it's a more gentle, up-and-down curved path.  In either case, the distance covered by the light inside the fiber is more than the straight length of the cable, and the time it takes it to come out the other end is more than its actual speed inside the glass would have meant if it could have traveled straight through the pipe.

2).  This problem talks about an optical fiber that's 1,200km long.  There is loss in optical fiber, and you're NOT going to get light all the way through a single piece of it that's something like 745 miles long.  It takes electronic repeaters, "boosters", and regenerators every few miles to keep it going, and these devices add "latency" or time delay in the process of going through them.  That delay in the electronics shows up as apparent delay through the fiber-optic cable, and it makes the speed through the glass appear to be slower than it actually is.
6 0
3 years ago
Read 2 more answers
Cousin Throckmorton is playing with the clothesline. One end of the clothesline is attached to a vertical post. Throcky holds th
Oksi-84 [34.3K]

Answer:

The  frequencies are  f_n  =  n (0.875 )

Explanation:

From the question we are told that

   The speed of the wave is  v  =  0.700 \  m/s

   The  length of vibrating  clothesline is  L  =  40.0 \  cm = 0.4 \ m

Generally the fundamental frequency is  mathematically represented as

        f =  \frac{v}{2 L  }

=>     f =  \frac{ 0.700 }{2 *  0.4   }

=>     f =  0.875 \  Hz

Now  this other frequencies of vibration experience by the clotheslines are know as harmonics and they are obtained by integer multiple of  the fundamental frequency

So  

   The  frequencies are mathematically represented as

       f_n  =  n  * f

=>     f_n  =  n (0.875 )

Where  n  =  1, 2, 3 ....

       

3 0
3 years ago
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