Answer:

The Magnitude of electric field is in the upward direction as shown directly towards the charge
.
Explanation:
Given:
- side of a square,

- charge on one corner of the square,

- charge on the remaining 3 corners of the square,

<u>Distance of the center from each corners</u>


∴Distance of center from corners, 
Now, electric field due to charges is given as:

<u>For charge
we have the field lines emerging out of the charge since it is positively charged:</u>

<u>Force by each of the charges at the remaining corners:</u>

<u> Now, net electric field in the vertical direction:</u>


<u>Now, net electric field in the horizontal direction:</u>


So the Magnitude of electric field is in the upward direction as shown directly towards the charge
.
Answer:
0.19m/s²
Explanation:
Initial velocity(u) = 50×1000/60×60
=13.88 m/s
Final velocity(v) = 36.5×1000/60×60
=10.13 m/s
Acceleration(a) = v-u/t
=10.13-13.88/19.5
a= -0.19m/s²
-a = 0.19m/s²
The magnitude of retar dation is 0.19m/s²
120 acceleration oh yeah i am sure about this
By using Lami's theorem formula, the tension in the supporting wires is 48.6 Newtons
TENSION
- Tension is also a force having Newton as S.I unit.
- The tension in the wire will be the same.
This question can be solved by using either vector diagram or by using Lami's theorem.
The sum of two given angles = 42 + 42 = 84 degrees
The third angle = 180 - 84 = 96 degrees.
Below is the Lami's theorem formula

Where
= 42 + 90 = 132 degrees
Y = 96 degrees
W = 65 N
By using the formula, we have

T/sin 132 = 65/sin96
Cross multiply
T = 0.743 x 65.57
T = 48.56 N
Therefore, the tension in the supporting wires is 48.6 Newtons approximately.
Learn more about Tension here: brainly.com/question/24994188