The volume of 0.555M KNO3 solution would contain 12.5 g of solute iss 223 mL.
<h3>What is the relationship between mass of solute and concentration of solution?</h3>
The mass of solute in a given volume of solution is related by the formula below:
- Molarity = mass/(molar mass * volume)
Therefore, volume of solution is given by:
Volume = Mass /molarity * molar mass
Molar mass of KNO₃ = 101 g/mol
Volume = 12.5/(0.555 * 101)
Volume = 0.223 L or 223 mL
In conclusion, the volume of the solution is obtained from the molarity of solution as well as mass and molar mass of solute.
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<h3>
Answer:</h3>
48.95% (m/v)
<h3>
Explanation:</h3>
From the question we are given;
- Mass of solute, NaCl is 186 g
- Volume of the solvent, water as 3.80 L or 380 mL
We are required to calculate the mass volume percent of solution;
How do we calculate the mass volume percent of a solution?
- To calculate the mass volume percent, we use the formula,
Mass volume percent = (mass of solute in g/Volume of solvent in mL) 100
= (186 g ÷ 380 mL)100
= 48.95%
Therefore, the mass volume percent of a NaCl solution is 48.95% (m/v).
Answer:
The structure of the atom.
Explanation:
The correct answer is - The structure of the atom.
Reason -
An atom is the smallest unit of matter that retains all of the chemical properties of an element.
The consumption of antacid affect urine pH by increasing the pH of urine. Sodium bicarbonate or antacid neutralizes the acidity in the stomach. It is expelled in the body through the urine by alkalizing it. Hope this answers the question.
Answer:
k = 6.31 x 10⁻³ min⁻¹
Explanation:
The equation required to solve this question is:
k = 0693 / t half-life
This equation is derived from the the equation from the radioctive first order reactions:
ln At/A₀ = -kt
where At is the number of isoopes after a time t , and A₀ is the number of of isotopes initially. The half-life is when the number of isotopes has decayed by a half, so
ln(1/2) = -kt half-life
-0.693 = - k t half-life
t half-life = 109.8 min
⇒ k = 0.693 / t half-life = 0.693 / 109.8 min = 6.31 x 10⁻³ min⁻¹