The y-component of the stone's velocity when it is 8 m below the hand is 14.86 m / s
v² = u² + 2 a s
s = Displacement
u = Initial velocity
a = Acceleration
u = 8 m / s
s = 8 m
v² = 8² + 2 * 9.8 * 8
v² = 64 + 156.8
v = √ 220.8
v = 14.86 m / s
The equation used to solve the problem is an equation of motion. These equations are designed to locate an object in motion using components such as velocity, displacement, acceleration and time.
Therefore, the y-component of the stone's velocity is 14.86 m / s
To know more about Equations of motion
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The height of the balcony may be calculated through the equation,
h = V₀t + 0.5gt²
where h is the height, V₀ is the initial velocity, g is the gravitational constant and t is time. Substituting the values given above,
h = (5 m/s)(2s) + 0.5(10 m/s²)(2 s)²
h = 30 m
Thus, the height of the balcony is 30 meters.
The force depends on the mass of both objects and the distance between them
F = G*m1*m2/r^2
So the force has a linear connection with the mass of both objects and a quadratic connection with the distance between the center of masses
Answer:
a)10.28 Nm
b)9.93 Nm
Explanation:
Let g = 9.81m/s2. First we can calculate the weight of the trophy
W = mg = 1.6 * 9.81 = 15.696 N
(a) The torque is product of force and its moment arm
T = WL = 15.696 * 0.655 = 10.28 Nm
(b) Suppose his arm makes an angle of 15 degree with respect to the horizontal line. We can still calculate the arm length, or the horizontal distance from the trophy to the champion:
Again, torque is product of force and its moment arm
