Answer:
See attached file for detailed answer.
Explanation:
Answer:
The speed is the same at 1.5 m/s while
The work done by the force F is 0.4335 J
Explanation:
Here we have angular acceleration α = v²/r
Force = ma = 2.8 × 1.5²/r₁
and ω₁ = v₁/r₁ = ω₂ = v₁/r₂
The distance moved by the force = 600 - 300 = 300 mm = 0.3 m
If the velocity is constant
The speed is 1.5 m/s while the work done is
2.8 × 1.5²1/(effective radius) ×0.3
r₁ = effective radius
2.8*9.81 = 2.8 × 1.5²/r₁
r₁ = 0.229
The work done by the force = 2.8 × 1.5²*1/r₁ *0.3 = 0.4335 J
Answer:
C is the answer if not c then b
Answer:
And Im still going with B..
Answer: Temperature T = 218.399K.
Explanation:
Q= 129W/m2
σ = 5.67 EXP -8W/m2K4
Q= σ x t^4
t = (Q/σ)^0.25
t= 218.399k