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Marysya12 [62]
3 years ago
6

What would most likely happen if a continental polar air mass clashed with the continental tropical air mass?

Chemistry
1 answer:
lakkis [162]3 years ago
7 0

Answer: PLease make me Brainliest

"They can bring anything from tropical warm and humid days to arctic cold depending on the type of air mass. Fronts form the boundaries of air masses with differing properties. The most severe weather usually occurs when dry-cold continental polar air clashes with warm-humid maritime tropical air."

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An object has a density of 0.73 g/cm3. Will the object sink or float in water?
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<h2>It'll float</h2><h2>Less than 1g/cm3 it'll float in water </h2>

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What would be another property that we Earthlings could use to classify stars?
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Answer: At the point when space experts take a gander at an article's range, they can decide its arrangement dependent on these frequencies. The most well-known technique stargazers use to decide the sythesis of stars, planets, and different articles is spectroscopy. This spread-out light is known as a range.

Explanation:

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Explain the reason that maps must change over time
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Because the place on the map can be changed to another shape by natural effects like faulting,folding , volcanism

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3 years ago
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A solution is prepared by dissolving 60.0 g of sucrose, C12H22O11, in 250. g of water at 25°C. What is the vapor pressure of the
Rina8888 [55]

Answer:

23.46 mmHg is the vapor pressure for the solution

Explanation:

To solve this problem we need to apply a colligative property, which is the lowering vapor pressure.

The formula for this is: P°- P' = P° . Xm

where P' is vapor pressure for solution and P°, vapor pressure for pure solvent.

Let's determine the Xm (mole fraction for solute)

We calculate the moles of the solute and the solvent and we sum each other:

Moles of solute: 60 g /342 g/mol = 0.175 moles of sucrose

Moles of solvent: 250 g / 18 g/mol = 13.8 moles of water

Total moles: 13.8 moles + 0.175 moles = 13.975 moles

Xm for solute: 0.175 moles / 13.975 moles = 0.0125

Let's replace data in the formula: 23.76 mmHg - P' = 23.76 mmHg . 0.0125

P' = - (23.76 mmHg . 0.0125 - 23.76 mmHg) → 23.46 mmHg

7 0
3 years ago
If I have 3.2 moles of gas at a pressure of 0.095 atm and at a temperature o 43 C what is the volume of the container that the g
andriy [413]

Answer

The volume of the container that the gas is in = 874.30 L

Explanation

Given:

Moles, n = 3.2 mol

Pressure, P = 0.095 atm

Temperature, T = 43 °C = (43 + 273.15 K) = 316.15 K

Molar gas constant, R = 0.0821 atm•L/mol•K

What to find:

The volume of the container that the gas occupied.

Step-by-step solution:

The volume of the container that the gas occupied can be calculated using the ideal gas equation.

\begin{gathered} PV=nRT \\  \\ \Rightarrow V=\frac{nRT}{P}=\frac{3.2mol\times0.0821atm•L/mol•K\times316.15K}{0.095atm} \\  \\ V=\frac{83.058928\text{ }atm•L}{0.095\text{ }atm}=874.30\text{ }L \end{gathered}

Therefore, the volume of the container that the gas occupied is 874.30 L

5 0
1 year ago
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