1.199 M is the concentration of KCI in the resulting solution.
<h3 /><h3>What are moles?</h3>
A mole is defined as 6.02214076 × 
of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
No.of moles of KCI
= 0.599 moles
Vol.of the solution,V= 500 ml
= 0.5 liter
Molarity
= 1.199 M
Hence, 1.199 M is the concentration of KCI in the resulting solution.
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Mass=density x volume, i.e. 1.03 x 85.32 = 87.88 g
Answer:
Mass = 57.05 g
Explanation:
Given data:
Volume of SO₂ = 20.0 L
Temperature = standard = 273 K
Pressure = standard = 1 atm
Mass of SO₂ = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm × 20.0 L / 0.0821 atm.L/ mol.K× 273 k
n = 20.0 / 22.41/mol
n = 0.89 mol
Mass of SO₂:
Mass = number of moles × molar mass
Mass = 0.89 mol × 64.1 g/mol
Mass = 57.05 g
Answer:
The correct answer is 0.11 mol O₂
Explanation:
The chemical equation for the reaction of acetylene (C₂H₂) with O₂ to produce carbon dioxide (CO₂) and water (H₂O) is the following:
2 C₂H₂(g) + 5 O₂(g) → 4 CO₂(g) + 2 H₂O(g)
The chemical equation is balanced : with the proper estequiometrical coefficients. According to this, 2 moles of C₂H₂ reacts with 5 moles of O₂ to give 4 moles of CO₂ and 2 moles of H₂O.
In order to calculate how many moles of O₂ are needed to produce 0.085 moles of CO₂, we multiply the 0.085 moles of CO₂ by the factor 5 moles O₂/4 moles CO₂ (because 4 moles of CO₂ are produced by 5 moles of O₂ according to the chemical equation):
0.085 moles CO₂ x (5 moles O₂/4 moles CO₂) = 0.10625 moles O₂ = 0.11 moles O₂
