Answer: 46.6 grams
Explanation:

Given : density of hexane = 0.660 g/ml
volume of hexane = 20 ml
Mass of hexane = 
moles of hexane =
According to stoichiometry :
2 moles of hexane reacts with 19 moles of oxygen
Thus 0.14 moles hexane will react with =
moles of oxygen
Mass of oxygen =
Thus minimum mass of oxygen required for the complete reaction of 20.0 mL of hexane is 46.6 grams.
Answer: 893.7K
Explanation:
From the question, we obtained the following:
V = 54L
n = 2.8moles
P = 3.8 atm
R = 0.082atm.L/mol /K
T =?
Applying the ideal gas equation, we have:
PV = nRT
T = PV /nR
T = (3.8x54)/(2.8x0.082)
T = 893.7K