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2 years ago

11

Which of the following most logically completes the argument below?

1 answer:

kolezko [41]2 years ago

6 0

Answer:

(E) a greatly increased number of small particles in Earth’s orbit would result in a blanket of reflections that would make certain valuable telescope observations impossible

Explanation:

The trade is one strong reflection for many weak reflections (and more dangerous near-Earth space travel).

None of the answer choices except the last one has anything to do with the effect of exploding a satellite. When you are arguing that exploding a satellite is ill conceived, you need to address specifically the effects of exploding the satellite.

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A 5kg rock is lifted 2m. Find the amount of work done.

lianna [129]

Answer:

98J

Explanation:

Given parameters:

Mass of rock = 5kg

Height = 2m

Unknown:

Work done = ?

Solution:

The amount of work done is given as:

Work done = Force x distance

Work done = Weight x height

Work done = mgH

Now insert the parameters and solve;

Work done = 5 x 9.8 x 2 = 98J

5 0

2 years ago

One gallon of paint covers an area of 25 m2. What is the thickness of the paint on the wall?

Flura [38]

Answer:

Explanation:

1 gal = 231 in³

231 in³ (2.54³ cm³/in³) = 3,785.411784 cm³

3,785.411784 cm³ (0.01³ m³/cm³) = 0.003785411784 m³

0.003785411784 m³ / 25 m² = 0.00015141647136 m

or approximately 0.15 mm

6 0

2 years ago

Travka [436]

Answer:

d I believe so

Explanation:

d yes?????

8 0

2 years ago

Elements of Music<br>Timbre<br>Dynamics<br>Rhythm<br>Form<br>Texture<br>Harmony<br>Style

rodikova [14]

Explanation:

Rhythm, Harmony, Timbre, Dynamics, Texture, and Form

7 0

2 years ago

An 67-kg jogger is heading due east at a speed of 2.3 m/s. A 70-kg jogger is heading 61 ° north of east at a speed of 1.3 m/s. F

ololo11 [35]

Answer

given,

mass of jogger = 67 kg

speed in east direction = 2.3 m/s

mass of jogger 2 = 70 Kg

speed = 1.3 m/s in 61 ° north of east.

jogger one

$P_1 = m_1 v_1 \hat{i}$

$P_1 = 67 \times 2.3\hat{i}$

$P_1 = 154.1 \hat{i}$

$P_2 = m_2 v_2 \hat{i} +m_2 v_2 \hat{j}$

$P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}$

$P_2 = 70\times 1.3 cos 61^0 \hat{i} +70\times 1.3 sin 61^0\hat{j}$

$P_2 = 44.12\hat{i} +79.59\hat{j}$

now

P = P₁ + P₂

$P = 198.22 \hat{i} +79.59 \hat{j}$

magnitude

$P = \sqrt{198.22^2 + 79.59^2}$

$P =213.60 kg.m/s$

$\theta = tan^{-1}\dfrac{79.59}{198.22}$

$\theta = 21.87$

the angle is $\theta = 21.87$ north of east

7 0

3 years ago