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Anastasy [175]
3 years ago
13

Suppose a soccer ball is kicked from the ground at an angle 20.0º above the horizontal at 8.00 m/s. The y-velocity is determined

to be 2.74 m/s. How long will the ball be in the air? Assume the ball lands at the same height at which it was kicked.
Physics
1 answer:
julia-pushkina [17]3 years ago
8 0

initial speed of the ball by which it is kicked is 8 m/s

now the angle at which it is kicked is 20 degree

here we will have

v_y = v sin20

v_y = 8 sin20 = 2.74 m/s

now we will have

\Delta y = v_y t + \frac{1}{2}at^2

so if the ball again land on the ground at same level then we have

\Delta y = 0

0 = 2.74 t - \frac{1}{2}(9.8) t^2

0 = 2.74 - 4.9 t

t = 0.56 s

so total time will be 0.56 s

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Answer: 244.05 J

Explanation:

To find speed  at 30 m above the ground use equation:

V²=Vo²-2Gs

V0=31.4m/s

s=30m

G=9.81m/s²

-----------------------

V²=31.4²-2*9.81*30

V²=985.96+588.6

V²=1574.56

V=39.68m/s ---speed of arrow on 30 m obove the ground

Use equation for kinetic enrgy:

Ke=mV²/2

m=0.155kg

V=39.68m/s

-------------------------

Ke=0.155kg*(39.68m/s)²/2

Ke=0.155*1574.5/2

Ke=244.05J

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