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Dvinal [7]
3 years ago
12

In order for gravitational potential energy to be stored, there must be _____.

Physics
1 answer:
trasher [3.6K]3 years ago
3 0

Answer: 1

an object positioned at some height in a gravitational field

Explanation:

Gravitational potential energy of an object is the energy stored due to position of the object or position at certain height relative to zero position.

Gravitational potential energy can also be expressed as object position at some height above or below zero position in a gravitational field

I think 1 and 2 make sense. But 1 make more sense than 2

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When we get out of the bed on a very cold morning, we feel that the air of the room is cold. But when we come back after staying
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Answer:

This is because the air outside is always cooler than the air inside, so after staying outside your body adapts to the cold air, when you come back inside, the cold air is still in you which makes the room seem warmer.

4 0
3 years ago
8. A driver starts his parked car and within 12 hours reaches a speed of 75km/h, as he travels
erastovalidia [21]

Answer:

56mph

Explanation:

7 0
3 years ago
Why are ocean currents important?
Lelu [443]
For the considerably longer periods– decades to millennia – which are relevant for climate change, the slightly larger heat capacity of the deep ocean<span> is </span>important. Ocean currents<span> and mixing by winds and waves can transport and redistribute heat to deeper </span>ocean<span> layers.</span>
4 0
3 years ago
By how much does the volume of an aluminum cube 4.00 cm on an edge increase when the cube is heated from 19.0°C to 67.0°C? The l
Genrish500 [490]

Answer:

The volume of an aluminum cube is 0.212 cm³.

Explanation:

Given that,

Edge of cube = 4.00 cm

Initial temperature = 19.0°C

Final temperature = 67.0°C

linear expansion coefficient \alpha=23.0\times10^{-6}/C^{\circ}

We need to calculate the volume expansion coefficient

Using formula of  volume expansion coefficient

\beta=3\alpha

Put the value into the formula

\beta=3\times23.0\times10^{-6}

\beta=0.000069=69\times10^{-6}/C^{\circ}

We need to calculate the volume

V= a^3

V=4^3

V=64\ cm^3

The change temperature of the cube is

\Delta T=T_{f}-T_{i}

Put the value into the formula

\Delta T=67-19 = 48^{\circ}C

We need to calculate the increases volume

Using formula of increases volume

\Delta V=V\beta\Delta T

Put the value into the formula

\Delta V=64\times69\times10^{-6}\times48

\Delta V=0.212\ cm^3

Hence, The volume of an aluminum cube is 0.212 cm³.

5 0
3 years ago
An electron in a vacuum is first accelerated by a voltage of 81700 V and then enters a region in which there is a uniform magnet
Vilka [71]

Answer:

Magnetic force is equal to 1.37\times 10^{-11}N

Explanation:

We have given electron is accelerated with a potential difference of 81700 volt.

Magnetic field B = 0.508 T

Angle between magnetic field and velocity \Theta =90^{0}

Mass of electron m=9.11\times 10^{-31}kg

Charge on electron e=1.6\times 10^{-19}C

By energy conservation.

\frac{1}{2}mv^2=qV

\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=1.6\times 10^{-19}\times 81700

v=169.4\times 10^6m/sec

Magnetic force on electron

F=qvBsin\Theta

F=1.6\times 10^{-19}\times 169.4\times 10^6\times 0.508\times sin90^{\circ}

=1.37\times 10^{-11}N

8 0
3 years ago
Read 2 more answers
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