Answer:
Newton’s Three Laws of Motion has a great impact.
Explanation:
Newton’s Three Laws of Motion has a great impact on the bowling game for the 2 students. When the student one throw ball to the student 2, the ball decrease its speed due to the gravity and opposing air. If these forces are removed from the system the ball will continue its motion till another force is applied on it. When the force applied to the ball it produces acceleration in the direction to the applied force. If the ball touches the ground it bounce back with equal force which is a reaction of the ground.
Answer:
D
Explanation:
The negative feedback is responsible for maintaining equilibrium (stability) in a system as it lessens effects, which is contrary to positive feedback which increases reaction and moves a system further away from equilibrium (stability), It does so by amplifying the effects of a product or event and occurs when something needs to happen quickly. e.g
- Insulin lowers down blood sugar levels, so when the body detects that it has too much sugar, the pancreas is prompted to release insulin and only stops when balance is achieved; hence, negative feedback.
- When there is a tear on the skin, a chemical is released. This chemical causes platelets in the blood to activate, hence they release a chemical which signals more platelets to activate, until the wound is clotted, positive feedback.
Answer:
Now since mass of reactant is equal to mass of the product after the reaction so we can say that mass conservation is applicable here
Explanation:
As we know that zinc reacts with copper sulfate
so the reaction is given as
![Zn + CuSO_4 --> ZnSO_4 + Cu](https://tex.z-dn.net/?f=Zn%20%2B%20CuSO_4%20--%3E%20ZnSO_4%20%2B%20Cu)
so here we have
![Zn = 10.1 g](https://tex.z-dn.net/?f=Zn%20%3D%2010.1%20g)
![CuSO_4 = 18.6 g](https://tex.z-dn.net/?f=CuSO_4%20%3D%2018.6%20g)
![ZnSO_4 = 20 g](https://tex.z-dn.net/?f=ZnSO_4%20%3D%2020%20g)
![Cu = 8.7 g](https://tex.z-dn.net/?f=Cu%20%3D%208.7%20g)
Now total mass of reactant is given as
![M_1 = 10.1 + 18.6 = 28.7 g](https://tex.z-dn.net/?f=M_1%20%3D%2010.1%20%2B%2018.6%20%3D%2028.7%20g)
Mass of the product is given as
![M_2 = 20 + 8.7 = 28.7 g](https://tex.z-dn.net/?f=M_2%20%3D%2020%20%2B%208.7%20%3D%2028.7%20g)
Now since mass of reactant is equal to mass of the product after the reaction so we can say that mass conservation is applicable here