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2 years ago

How Do I get A Picture For My Profile, It keeps saying my pistures won't work

Physics

1 answer:

EleoNora [17]2 years ago

7 0

Answer:

So whenever it won't work, try to find a new pic because your current one is too small / big. Type in the size, for example, 10x10 cool backgrounds, and pick one. You can do any size and any background so long as it fits. Also don't multiply 10x10 whenever you're dealing with backgrounds.

Explanation:

I hope this helped!

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What is the difference between circumstances and circumference??<br><br>pls ans asap

dimulka [17.4K]

Answer:

understand

Explanation:

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6 0

3 years ago

Acceleration is always measured in meters per second squared. Why is acceleration not measured in meters per second like speed?

Taya2010 [7]

Answer:

Because 'distance per second' is a velocity, not an acceleration.

Explanation:

Because 'distance per second' is a velocity, not an acceleration. For example, at 1 m/s an object is travelling a distance of 1 metre every second. But a rate of acceleration is a steady increase in velocity. So at 1 m/s^2, an object's velocity is increasing by 1 m/s every second.

6 0

2 years ago

What is the gravitational force between Mars and the sun? 7.43 × 1030 N 1.79 × 1026 N 1.65 × 1021 N 3.76 × 1032 N

VMariaS [17]

The gravitational force between Mars and the Sun is $1.65\cdot 10^{21} N$

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

$F=G\frac{m_1 m_2}{r^2}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, we have:

$m_1 = 1.99\cdot 10^{30} kg$ is the mass of the Sun

$m_2 = 6.39\cdot 10^{23} kg$ is the mass of Mars

$r=229\cdot 10^6 km = 229\cdot 10^9 m$ is the average distance Mars-Sun

Substituting into the equation, we find the gravitational force:

$F=(6.67\cdot 10^{-11})\frac{(1.99\cdot 10^{30})(6.39\cdot 10^{23})}{(229\cdot 10^9)^2}=1.62\cdot 10^{21} N$

So, the closest answer is

$1.65\cdot 10^{21} N$

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

4 0

3 years ago

Do Small objects exert no gravitational force ? True or false

Zanzabum

Answer:

False -

F = G M1 M2 / R^2

So F depends on M1 and M2 and as long either is not zero there will be a gravitational force between them.

6 0

2 years ago

Fighter jet starting from airbase A flies 300 km east , then 350 km at 30° west of north and then 150km north to arrive finally

Tems11 [23]

A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North.
It means : at 60° North of West. So the distance from the final point to the line AM is :
350 · cos 60° = 350 · 0.866 = 303.1 km
Let`s assume that there is a line N on AM.
AN = 125 km and NM = 175 km.
And finally jet fighter flies 150 km North to arrive at airbase B.
NB = 303.1 + 150 = 453.1 km
Then we can use the Pythagorean theorem.
d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km
Also foe a direction: cos α = 125 / 470 = 0.266
α = cos^(-1) 0.266 = 74.6°
90° - 74.6° = 15.4°
Answer: The distance between the airbase A and B is 470 km.
Direction is : 15.4° East from the North.

4 0

3 years ago