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mr Goodwill [35]

3 years ago

9

To make sure that the white powder was all sodium chloride and not mixed with sodium hydrogen carbonate, would you need to add a

little less or a little more hydrochloric acid to the reaction?

1 answer:

TiliK225 [7]3 years ago

6 0

Answer: i hope you thought this was an actual answer

Explanation:

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Two of the substances in part 1 are ionic. which factors will result in a stronger ionic bond overall?

olya-2409 [2.1K]

Greater absolute charge
- This is because ionic bond results from stronger electrostatic forces of attraction.
- The higher the value of charges q₁ and q₂ the stronger will be the ionic bond.

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What is Gallium Sulfide(Ga2S3).<br> Ionic or Covalent?

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Which does your digestive system use to break down food molecules? Bases or Acids

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Heat in a substance is an example of ________ energy. A. phase B. kinetic C. potential D. evaporative

lisov135 [29]

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In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

7 0

3 years ago