The mixture can be separated into three separate components by using a centrifuge and a separating funnel.
A centrifuge is used to separate a solid that is held in suspension by a liquid. In this case a solid dissolved in water. In contrast, a separating funnel is used to separate two immiscible liquids.
-First take the flask containing the two immiscible liquids and pour contents in to a closed separating funnel.
- The most dense liquid will settle at the bottom, then open the separating funnel valve to collect contents of dense liquid into a flask.
- The remaining liquid on the separating funnel can be collected in a different flask.
-Now take the liquid that is a solution of a solid in water and pour in a test tube. Place the contents in a centrifuge.
- Centrifuge at high speed until the solid sinks to the bottom of the test tube, then decant the liquid into a flask and the solid remains in the test tube
<u>Answer:</u>
<em>B Mass </em>
<em>D Force </em>
<em>E Acceleration</em>
<u>Explanation:</u>
We know that
Force = mass × acceleration
F = m × a
The unit of force is newtons
The unit of mass is kg and
the unit of acceleration is
Force and acceleration are vector quantities and mass is a scalar quantity.
Newton's 2nd law of motion states that acceleration is directly proportional to net force and inversely proportional to mass.
he result is the equation
∑
Answer:
0.3139 nm
Explanation:
First of all, let's Calculate the average density of the Cr −Ta alloy;
Formula to get it is;
ρ_avg = 100/[(C_cr/ρ_cr) + (C_ta/ρ_ta)]
We are given;
C_cr = 26%
C_ta = 74%
ρ_cr = 7.13 g/cm³
ρ_ta = 16.6 g/cm³
Thus;
ρ_avg = 100/[(26/7.13) + (74/16.6)]
ρ_avg = 12.34 g/cm³
Similarly, let's Calculate the average atomic weight;
A_avg = 100/[(C_cr/A_cr) + (C_ta/A_ta)]
We are given;
A_cr = 52 g/mol
A_ta = 180.95 g/mol
Thus;
A_avg = 100/[(24/52) + (74/180.95)]
A_avg = 114.88 g/mol
Formula for the volume of the unit cell is;
V = n(A_avg)/(N_A × ρ_avg)
Where;
n is number of atoms in the cell which in this case = 2
N_A is avogadro's number = 6.022 × 10^(23)
Thus;
V = (2 × 114.88)/(6.022 × 10^(23) × 12.34)
V = 30.92 × 10^(-24) cm³
Length of the unit cell edge length is given by the formula;
a = ∛V
Thus;
a = ∛(30.92 × 10^(-24))
a = 0.00000003139 cm
Converting to metre, we have;
a = 0.3139 × 10^(-9) m = 0.3139 nm
How fast it changes position in time is the objects speed