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Bumek [7]
3 years ago
10

How do you know if a chemical reaction has occurred?

Chemistry
1 answer:
never [62]3 years ago
3 0
If one or more of the following occur: Gas formation, precipitate formation, color change, temperature change, or odor

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2339.1 in standard form or scientific notation
zhenek [66]
See under both it comes

6 0
3 years ago
Read 2 more answers
3. Crystalline structural unit of barium metal is a body-centered cubic cell. The edge length of the unit cell is 5.02x10-8 cm.
tiny-mole [99]

Answer:

The Avogadro's  number is N_A     =  6.02289 *10^{23}

Explanation:

From the question we are told that

   The edge length is  L   = 5.02 * 10^{-8} \ cm= \frac{5.02 * 10^{-8} }{100}  =  5.02 * 10^{-10}

    The density of the metal is \rho =  5.30\ g/cm^3 = 5.30 * \frac{g}{cm^3}  * \frac{1*10^6}{1*10^3} = 5.30 *10^3kg/m^3

     The molar mass of  Ba is  Z  =  137.3 \ g/mol = \frac{137.3}{1000} =  0.1373 \  kg / mol

     

Generally the volume of a unit cell is  

       V =  L^3

substituting value

        V =  [5.02 *10^{-10}]^3

         V = 1.265*10^{-28}\ m^3  

From the question we are told that 68% of the unit cell is occupied by Ba atoms and that the structure is a metal which implies that the crystalline structure will be  (BCC),

The volume of barium atom is  

        V_a  =  \frac{V}{2}  * 0.68

substituting value

        V_a  =  \frac{ 1.265*10^{-28}}{2}  * 0.68

        V_a  = 4.301 *10^{-29} \ m^3

The Molar mass of barium is mathematically represented as

      Z  =  N_A V_a *  \rho

Where N_A is the Avogadro's number

 So  

      N_A     =   \frac{ Z}{ V_a *  \rho}

substituting value

     N_A     =   \frac{ 0.1373}{ 4.301*10^{-29} *  5.3*10^{3}}

     N_A     =  6.02289 *10^{23}

4 0
3 years ago
A(n) acid or base will dissociate completely in water, whereas a(n) acid or base dissociates very little in water.
EleoNora [17]

A(n) strong acid or base will dissociate completely in water, whereas a(n) weak acid or base dissociates very little in water.

Strong acids are defined as any acid that completely dissociates into ions. It is a weak acid if dissociation is less than 100%.

Strong bases are defined as any acid that completely dissociates into ions. It is a weak base if dissociation is less than 100%.

Not every acid or base ionizes or dissociates to the same degree. This supports the claim that not all acids and bases have the same ability to produce H+ and OH- ions in solution.

The adjectives "strong" and "weak" describe how strong an acid or base is. The ability of acidic and basic solutions to conduct electricity is referred to as strong and weak.

Strong electrical conductivity indicates that an acid or base is a strong acid or base. A weak acid or base is one that conducts electricity only slightly.

Learn more about Acid & Base here brainly.com/question/9836972

#SPJ4

5 0
1 year ago
Riya rides his bike 63 miles in 270 minutes. What is his average speed in miles per hour? Be sure to include the equation for sp
bekas [8.4K]

Answer:

14mph

Explanation:

270 minutes = 4 hr and 1/2hr

63 miles = 63/4.5 = 14 miles per hour

Making the speed 14mph

Equation = h = 4.5     

(4h x 4h ) + (1 x 311/100) = 60

= 4h x 4h +( 1 x 311/100) =60

= 16h^2 + (1 x 311/100) =60

= 256h + (1 x 311/100) =60

= 256h + 14 = 60

= 270h  =  60

= h = 4.5    

8 0
3 years ago
According to Markovnikov's rule of the electrophilic addition to an alkene, the electrophile, usually a proton, is more likely t
Natali [406]

Answer:

Explanation:

To fill in the gaps with the appropriate words, we need to rewrite the whole text in the question while adding the right answers to it.

According  \ to   \ Markovnikov's \  rule  \ of  \ the  \ electrophilic \  addition   \ to \  an \  alkene,  \\ \\ the  \ electrophile,  \ usually,  \ a  \ proton,  \ is  \ more  \ likely \  to  \ add \  to \  the \ \mathbf{less  \ substituted \ carbon}  \\ \\ \  in \  a  \ double \  bond.

This  \ arrangement \  place \  the \  intermediate \  carbocation \  on  \ the \  \mathbf{more \ substituted \ carbon.}Which  \ stabilizer \  it  \ with \ the\  presence \  of  \ \mathbf{more \  substituents}  \ the  \ major \  product \ of

the  \ reaction \  following \  markovnikov  \ rules \  the  \ \mathbf{nucleophile}  \ will \  then \ end \  up

with \  the  \ m ore  \ substituted \  carbon  \ in  \ the \  double \ bond.

3 0
3 years ago
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