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3 years ago

A detrital rock is named

1 answer:

4 0

A detrital rock is named as clastic sedimentary rocks

It is a rock formed from an amalgamation of several types of rock particles, through the process of sedimentation.sedimentation means settling from a fluid which could either be water or gas,

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(II) The platter of the hard drive of a computer rotates at 7200 rpm (rpm = revolutions per minute = rev/min). (a) What is the a

Rama09 [41]

Answer:

Explanation:

Given:

Angular velocity, w = 7200 rpm

Radius, r = 3 cm

= 0.03 m

1 bit = 0.5 × 10^-6 m

1 rev = 2pi rad

7200 rev/min × 2pi rad/1 rev × 1 min/60 sec

= 753.98 rad/s

Linear velocity, v = r × w

= 0.03 × 753.98

= 22.62 m/s

1 bit = 0.5 × 10^-6 m

Velocity = 22.62 m/s

1 bit/0.5 × 10^-6 m × 22.62 m/s

= 4.524 × 10^7 bits/s

5 0

4 years ago

A rifle is aimed horizontally at a target 30m away. The bullet hits the target 2.9 cm below the aiming point. What is the bullet

Luden [163]

Answer:

Speed of bullet = 389.61 m/s.

Explanation:

Considering the vertical motion of bullet

Initial vertical speed = 0 m/s

Vertical displacement = 2.9 cm = 0.029 m

Vertical acceleration = 9.81 m/s²

Substituting in s = ut + 0.5at²

0.029 = 0 x t + 0.5 x 9.81 x t²

t = 0.077 s

So ball hits the target after 0.077 s.

Now considering the vertical motion of bullet

Time = 0.077 s

Horizontal displacement = 30 m

Horizontal acceleration = 0 m/s²

Substituting in s = ut + 0.5at²

30 = u x 0.077 + 0.5 x 0 x 0.077²

u = 389.61 m/s

Speed of bullet = 389.61 m/s.

6 0

3 years ago

Read 2 more answers

What energy changes take place in a glowing electric bulb

ehidna [41]

Answer:

electrical energy change into heat and light energy.

8 0

3 years ago

An astronaut is being tested in a centrifuge. The centrifuge has a radius of 11.0 m and, in starting, rotates according to θ = 0

Mazyrski [523]

Answer:

a) 1.248 rad/s

b) 13.728 m/s

c) 0.52 rad/s^2

d) 17.132m/s^2

Explanation:

You have that the angles described by a astronaut is given by:

$\theta=0.260t^2$

(a) To find the angular velocity of the astronaut you use the derivative og the angle respect to time:

$\omega=\frac{d\theta}{dt}=\frac{d}{dt}[0.260t^2]=0.52t$

Then, you evaluate for t=2.40 s:

$\omega=0.52(2.40)=1.248\frac{rad}{s}$

(b) The linear velocity is calculated by using the following formula:

$v=\omega r$

r: radius if the trajectory of the astronaut = 11.0m

You replace r and w and obtain:

$v=(1.248\frac{rad}{s})(11.0m)=13.728\frac{m}{s}$

(c) The tangential acceleration is:

$a_T=\alpha r\\\\\alpha=\frac{\omega^2}{2\theta}=\frac{(1.248rad/s)^2}{2(0.260(2.40s)^2)}=0.52\frac{rad}{s^2}$

(d) The radial acceleration is:

$a_r=\frac{v^2}{r}=\frac{(13.728m/s)^2}{11.0m}=17.132\frac{m}{s^2}$

4 0

3 years ago

How much heat is needed to raise the temperature of 10g of water by 16°C?

Nina [5.8K]

26°F

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5 0

3 years ago