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3 years ago

What is the heat required to vaporize 650 grams of a liquid with a heat of vaporization of 723 joules/grams?

Chemistry

1 answer:

wolverine [178]3 years ago

3 0

Your answer would be E. 470,000 J

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What is chlorine's atomic number and mass

makkiz [27]

$\red{⭐hello my \: friend!}$

chlorine's atomic number and mass :

35,453 u

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☝️follow the rules of brainly!

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3 years ago

4.8 moles of Kl are dissolved in 850 mL of water. What is the molarity of the solutions?

AURORKA [14]

Hey there!

Molarity = 4.8/850 x 1000 =5.647mol/lit or 5.65M

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1 year ago

Differentiate between short period and long period in modern periodic table

AfilCa [17]

The difference between short period and long period is based upon the number of elements in each period. Shortest period is the first period which contains elements, while the longest period is the 6th period which contains 32 elements.

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3 years ago

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Who wants to be a doctor

xenn [34]

Answer:

maybe, but id rather do automotive stuff, thats my second option.

Explanation:

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2 years ago

2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2

nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with $H_2$ to form $CH_4$ and $H_2O$ . balanced reaction is:

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

No. of moles of CO = 0.800 mol

No. of moles of $H_2$ = 2.40 mol

Volume = 8.00 L

Concentration = $\frac{Moles}{Volume\ in\ L}$

Concentration of CO = $\frac{0.800}{8.00} = 0.100\ mol/L$

Concentration of $H_2$ = $\frac{2.40}{8.00} = 0.300\ mol/L$

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

Initial 0.100 0.300 0 0

equi. 0.100 -x 0.300 - 3x x x

It is given that,

at equilibrium $H_2O (x)$ = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium $H_2$ = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium $CH_4$ = 0.0386 M

$Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}$

$Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90$

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3 years ago