1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vanyuwa [196]
3 years ago
14

What is the heat required to vaporize 650 grams of a liquid with a heat of vaporization of 723 joules/grams?

Chemistry
1 answer:
wolverine [178]3 years ago
3 0

Your answer would be E. 470,000 J

You might be interested in
What is chlorine's atomic number and mass
makkiz [27]

\red{⭐hello my \: friend!}

chlorine's atomic number and mass :

35,453 u

\blue{⭐have  good  studies!}

☝️follow the rules of brainly!

8 0
3 years ago
4.8 moles of Kl are dissolved in 850 mL of water. What is the molarity of the solutions?
AURORKA [14]
Hey there!

Molarity = 4.8/850 x 1000 =5.647mol/lit or 5.65M

Hope this helps you dear :)
Have a good day :)
4 0
1 year ago
Differentiate between short period and long period in modern periodic table​
AfilCa [17]
The difference between short period and long period is based upon the number of elements in each period. Shortest period is the first period which contains elements, while the longest period is the 6th period which contains 32 elements.
8 0
3 years ago
Read 2 more answers
Who wants to be a doctor
xenn [34]

Answer:

maybe, but id rather do automotive stuff, thats my second option.

Explanation:

7 0
2 years ago
2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2
nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with H_2 to form CH_4 and H_2O. balanced reaction is:

CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

No. of moles of CO = 0.800 mol

No. of moles of H_2 = 2.40 mol

Volume = 8.00 L

Concentration = \frac{Moles}{Volume\ in\ L}

Concentration of CO = \frac{0.800}{8.00} = 0.100\ mol/L

Concentration of H_2 = \frac{2.40}{8.00} = 0.300\ mol/L

                 CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium H_2O (x) = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium H_2 = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium CH_4 = 0.0386 M

Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}

Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90

8 0
3 years ago
Other questions:
  • How many atoms of a chlorine element would be needed to react with one atomic of helium
    13·1 answer
  • Please can I have help on these two questions I’ll be very grateful!!!!!!
    7·1 answer
  • Throughput is a term that refers to the amount of ?
    8·1 answer
  • What volume is occupied by 10.0 moles of ammonia, Nh3, at standard conditions?
    6·1 answer
  • How many molecules are in 15 grams of Oxygen gas?
    13·1 answer
  • How many mL of a 4.50 (m/v)% solution would contain 23.0 g of solute?
    12·2 answers
  • Write the empirical formulas of the following compounds: (a) Al2Br6, (b) Na2S2O4, (c) N2O5, (d) K2Cr2O7, (e)H2C2O4.
    15·1 answer
  • An atom has 13 protons and 14 neutrons. what is its mass number?
    8·1 answer
  • How many atoms are in 15 moles of cadmium?
    12·2 answers
  • Nitrogen dioxide is used industrially to produce nitric acid, but it contributes to acid rain and photochemical smog. What volum
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!