Answer:
Explanation:Required formula is
W=F *S
W=work =?
F=force =5N
S=displacement =0.5m
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Answer:
Electron groups could be considered as Lone pair electrons and bonded pairs of electrons.
Answer: Option D & B
Explanation:
The two or more electrons can be bonded by single bond, double bond, covalent bond of electrons can simply be lone pair of electrons. Unshared pair of electrons are generally termed as lone pair of electrons in an atom which are generally present in the outermost shell of atoms. Hence electron groups can be determined by bonded pairs and lone pairs of electrons.
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For the given question the answer to the first part is that frequency of sound will be 404.76 Hz. and answer to the second part will be that the initial frequency for which that place will have the highest level of sound intensity
Given, the speed of sound 340 m/s
a) L1 + L2 = 3.5 m
and Ld = | L1 - L2 | = ( 1.75 + 0.21 ) - (1.75 - 0.21 ) = 1.96 - 1.54 = 0.42 m
Ld = λ/2
λ = 2Ld = 2×0.42 = 0.84 m
and finally,
f = v/λ
f = 340/0.84
f = 404.76 hertz
Frequency came out to be 404.76 hertz in this case
b) For the first frequency
0.42 = λ
f = v/λ
f = 340 / 0.42
f = 809.52 Hertz
Frequency came out to be 809.52 Hertz in this case.
To conclude with we can say that the Frequency of the sound in case on came out to be 404.76 hertz which is approximately 405 Hz after applying all the concepts and calculations, in second case first frequency for which that location will be a maximum of sound intensity came out to be 809.52 Hertz after applying all the concepts and calculations.
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The wavelength of the light that are not reflected in the air is,
λ5= 600 nm, λ6= 500 nm, λ7=428 nm.
<u>Explanation:</u>
- For the above problem, we have the case as no<n1 and n2 < n1 .
- so we have(1<1.5;1.4<1.5)To find the wavelengths of the light that is not reflected in the air.
- Since the phase changes are not common on both the surfaces/
- we have the formula, λ=2d n²/m ( where m=1,2,3,4,5...)
- solving the problem we get,
- λ5= 600 nm, λ6= 500 nm, λ7=428 nm
- The wavelength of the light that are not reflected in the air is,
λ5= 600 nm, λ6= 500 nm, λ7=428 nm.