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3 years ago

If your seeking nutritional advice what credentials would you look for

Physics

1 answer:

7nadin3 [17]3 years ago

6 0

Look for fiber (for aid in digestion), carbohydrates (for quick energy), and fats (for long term energy)

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Technician A says that the governor is used to measure vehicle speed in a hydraulically-controlled automatic transmission. Techn

igor_vitrenko [27]

Answer:

Both technicians are correct

Explanation:

In automobiles, governors are being used. Governors are also known for speed limiters as they can regulate and measure the speed of the automobile.

Hydraulic Transmission: Shifting is controlled by mechanical sensors according to vehicle speed and throttle position/manifold vacuum through valving operated by hydraulic 'pilot' signals.

Electronic Transmission: Shifting is controlled by an on-board computer that receives signals from electronic sensors.

3 0

2 years ago

A very good insulator has an R-value of 29. The material's heat transfer coefficient is

Fittoniya [83]

Answer:

b. 0.034

Explanation:

The heat transfer coefficient of a material (U-value) is equal to the reciprocal of its R-value, therefore:

$U = \frac{1}{R}$

where

R is the R-value of the material

For the insulator in this problem,

R = 29

Substituting into the equation, we find the heat transfer coefficient:

$U=\frac{1}{29}=0.034$

4 0

2 years ago

When the velocity of a mass on a spring is zero, the acceleration is at

Akimi4 [234]

Answer:

A maximum

Explanation:

When displacement is maximum, velocity is Zero and vice versa

When displacement is maximum, acceleration is maximum and when it is zero, acc. Is zero

3 0

3 years ago

Agata [3.3K]

Answer:

7. the ball with a mass of 8.0kg

8.1225 kg

9.4.2 kg-m/sec

10.15m/sec

11.0.001kgm/sec

7 0

2 years ago

In a 200-turn automobile alternator, the magnetic flux in each turn is ΦB = 2.50 10-4 cos ωt, where ΦB is in webers, ω is the an

n200080 [17]

Answer:

$10.63952sin(209.43951t)$

10.63952 V

Explanation:

$N_t$ = Number of turns = 200

$\phi_B$ = Magnetic flux = $2.5\times 10^{-4}cos(\omega t)$

$\omega_e$ = Engine angular speed = $1\times 10^{3}\ rpm$

Alternator angular speed is given by

$N_a=2\times \omega_e\\\Rightarrow N_a=2\times 1\times 10^{3}\\\Rightarrow N_a=2\times 10^{3}\ rpm$

$\omega=N_a\dfrac{2\pi}{60}\\\Rightarrow \omega=2\times 10^{3}\dfrac{2\pi}{60}\\\Rightarrow \omega=209.43951\ rad/s$

Induced emf is given by

$\epsilon=-N_t\dfrac{d\phi_B}{dt}\\\Rightarrow \epsilon=-200\dfrac{d}{dt}2.54\times 10^{-4}cos(209.43951 t)\\\Rightarrow \epsilon=200\times 2.54\times 10^{-4}\times 209.43951 sin(209.43951t)\\\Rightarrow \epsilon=10.63952sin(209.43951t)$

The function is $10.63952sin(209.43951t)$

The induced maximum emf is 10.63952 V

5 0

2 years ago