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spayn [35]
3 years ago
10

In the metric system of units (S.I), the basic unit of length is ___?

Chemistry
1 answer:
myrzilka [38]3 years ago
6 0

Answer:

meters

Explanation:

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Match the term with the definition.
Tom [10]
Condensation goes with A.

Evaporation goes with C.

Sublimation goes with B.

Freezing goes with D.
6 0
3 years ago
5.60 g of an unknown gas at STP fills a 500 mL flask. What is the molar mass of the gas
ale4655 [162]

Hey there!

From ideal gas equation we know,  PV = nRT

All the terms have their usual significance.

PV =w/M * RT

( where , n is number of moles = w/M,   we = weight of gas, M = molecular weight of the gas)

Therefore,  PV = wRT/M

At standard conditions ,  value of pressure, P = 1atm and standard temperature, T = 273K

And value of universal gas constant, R = 0.082 lit. atm. K⁻¹.mol⁻¹

Given that, weight of gas,

w = 5.60g and volume of gas,

V = 500mL = 0.5 Liters

Therefore, substituting all the value, we get   :

  Molar mass = 5.60 * 0.082 * 273 / 1 * 0.5

   Molar mass = 250.7232 g/mole

3 0
4 years ago
How many grams of NaOh are produced with the reaction of 5.00 moles of water?
dusya [7]

Answer:

200g

Explanation:

Step 1:

The balanced equation for the reaction.

2Na + 2H2O —> 2NaOH + H2

Step 2:

Determination of the number of mole of NaOH produced by the reaction. This is illustrated below:

From the balanced equation above,

2 moles of H2O produced 2 moles of NaOH.

Therefore, 5 moles of H2O will also produce 5 moles of NaOH.

Step 3:

Conversion of 5 moles of NaOH to grams. This is illustrated below:

Number of mole of NaOH = 5 moles

Molar Mass of NaOH = 23 + 1 + 16 = 40g/mol

Mass of NaOH =?

Mass = number of mole x molar Mass

Mass of NaOH = 5 x 40

Mass of NaOH = 200g

6 0
3 years ago
100 points to the person who can answer these 4 questions
Vinil7 [7]

Answer:

....,................................

Explanation:

1= A

2=D

3=C

4=C

8 0
3 years ago
How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci
horsena [70]

Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

CaCO₃ +  2HCl  →  CaCl₂  + CO₂  +  H₂O

Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g

5 0
4 years ago
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