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Montano1993 [528]
2 years ago
12

Why should you use an iron hammer instead of a wooden hammer?​

Physics
1 answer:
riadik2000 [5.3K]2 years ago
5 0

Answer:

more durability and easier to pound a hammer with the heavy weight.

Explanation:

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Temperature of the resistor in an RC circuit. In this problem we will look at the temperature response of the resist
fomenos

RC circuit determines the capacitor's charging rate.

  • In RC (resistive and capacitive) circuits, a capacitor's time constant is the number of seconds required to charge it to 63.2% of the input voltage.
  • This duration is described by a single time constant. After two time constants, the capacitor will be charged to 86.5% of the input voltage.
  • The RC time constant, also referred to as tau, is the time constant (in seconds) of an RC circuit and is obtained by multiplying the circuit resistance (in ohms) by the circuit capacitance (in farads), This transient reaction time T is stated in terms of = R x C, where R is the resistor value in ohms and C is the capacitor value in farads.

Learn more about  RC circuits here brainly.com/question/13450553

#SPJ4.

4 0
2 years ago
Two loudspeakers (A and B) are 3.20m apart and emitting a sound with a frequency of 400Hz. An observer is 2.10m directly in fron
TiliK225 [7]

Answer:

The observer hears a loud sound

Explanation:

In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.

You first calculate the distance between the observer and the loudspeakers.

The distances are given by:

d1: distance to loudspeaker A = 2.10m

d2: distance to loudspeaker B

d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m

Next, you calculate the wavelength of the sound waves by using the following formula:

\lambda=\frac{v_s}{f}

vs: speed of sound =  343 m/s

f: frequency of the waves = 400Hz

λ: wavelength

\lambda=\frac{343m/s}{400Hz}=0.8575m

Next, you calculate the path difference between the distance from the observer to the loudspeakers:

\Delta d=3.827m-2.10m=1.727m

You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:

\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2

Then, there will be a constructive interference, and the sound who the observer hears is loud.

5 0
3 years ago
A force that pushes or pulls is known as
xeze [42]

Answer:

A force that pushes or pulls is known as Newton's third law of Motion.

Explanation:

Newton's Third Law of Motion. Newton's Third Law of Motion states that for each action, there's an equal and opposite reaction. What this suggests is that pushing on an object causes that object to keep off against you, the precise same amount, but within the other way.

7 0
3 years ago
Read 2 more answers
HELP FAST MARKING BRAINLEST A neutral electroscope is touched with a positively charged rod. After the rod is removed the electr
ELEN [110]

on touching electroscope gets positively charged, so answer is B. conduction

5 0
3 years ago
If someone is driving 100 miles in 60 minutes then drives 150 miles in 100 minutes west, what is his acceleration rate.
Sliva [168]

Answer:

his acceleration rate is -0.00186 m/s²

Explanation:

Given;

initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)

time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s

final position of the car, x₁ = 150 miles = 241,350 m

time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s

The initial velocity is calculated as;

u = 160, 900 m / 3,600 s

u = 44.694 m/s

The final velocity is calculated as;

v = 241,350 m / 6,000 s

v = 40.225 m/s

The acceleration is calculated as;

a = \frac{\Delta V}{\Delta t} = \frac{v- u}{t_1 - t_ 0} = \frac{40.225  - 44.694}{6000-3600} = -0.00186 \ m/s^2\\\\

Therefore, his acceleration rate is -0.00186 m/s²

6 0
3 years ago
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