All categories

4 years ago

What does a given point represent on a line graph?

1 answer:

4 0

I've never heard it stated this way, but I guess you might say that a single point
on a line graph represents a single solution to the equation of the graph.

You might be interested in

Two balls of equal mass are thrown horizontally with the same initial velocity. They hit identical stationary boxes resting on a

11111nata11111 [884]

Answer:

The box 1 moves faster.

Explanation:

lets

Mass =m kg

Initial velocity = u m/s

Initial velocity of box = 0 m/s

Let stake mass of block = m

When ball bounces back:

The final speed of the box = v

Final speed of ball = - u

Pi = Pf ( From linear momentum conservation)

m x u + m x 0 = m ( - u) + m v

mu + mu = m v

v= 2 u

When ball get stuck :

The final speed of ball and box = v

Pi = Pf ( From linear momentum conservation)

m x u + m x 0 = (m+m) v

v= u /2

So the box 1 moves faster.

6 0

4 years ago

Which illusion or test was most difficult for you to perceive correctly? Why do you think this particular illusion was so challe

Elan Coil [88]

Answer:

a condition in which is real or imagined in fear are difficult to control

7 0

3 years ago

The difference in potential between the accelerating plates of a TV set is about 24 kV. The distance between these plates is 1.5

ryzh [129]

Answer:

So electric field between the plates will be equal to $1600\times 10^3KN/C$

Explanation:

We have given potential difference between accelerating plates = 24 KV = 24000 volt

Distance between the plates d = 1.5 cm = 0.015 m

We know that potential difference is given by V = Ed, here E is electric field and d is distance between plates

So $24000=E\times 0.015$

E = 1600000 N/C = $1600\times 10^3KN/C$

So electric field between plates will be equal to $1600\times 10^3KN/C$

7 0

3 years ago

A spaceship ferrying workers to moon Base i takes a straight-line pat from the earth to the moon, a distance of 384,000km, Suppo

GrogVix [38]

Answer:

95.78125%

18000 m/s

22233.33 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v=u+at\\\Rightarrow v=0+20\times 15\times 60\\\Rightarrow v=18000\ m/s$

The velocity of the rocket at the end of the first 15 minutes is 18000 m/s which is the maximum speed of the rocket in the complete journey.

Distance traveled while speeding up

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 20\times 900^2\\\Rightarrow s=8100000\ m$

Distance traveled while slowing down

$s=18000\times 900+\dfrac{1}{2}\times -20\times 900^2\\\Rightarrow s=8100000\ m$

Distance traveled during constant speed

$384000000-(2\times 8100000)=367800000\ m$

Fraction

$\dfrac{367800000}{384000000}\times 100=95.78125\ \%$

Fraction of the total distance is traveled at constant speed is 95.78125%

Time taken at constant speed

$t=\dfrac{367800000}{18000}=20433.33\ s$

Total time taken is $900+20433.33+900=22233.33\ s$

6 0

3 years ago

Which one i need help

Lostsunrise [7]

Answer:

Explanation:

7 0

3 years ago