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jonny [76]
4 years ago
14

Traditional explosives use the energy released by chemical reactions. Nuclear weapons use the energy released by nuclear reactio

ns. Why are nuclear weapons much more destructive than traditional explosives? Question 16 options: A. Chemical reactions can release much more energy than nuclear reactions B. Chemical reactions always use more energy than they release Nuclear weapons always contain more chemicals than traditional explosive C. Chemical reactions always release more energy than they use D. Nuclear reactions can release much more energy than chemical reactions
Physics
2 answers:
lawyer [7]4 years ago
5 0
I believe the correct answer from the choices listed above is option D. Nu<span>clear weapons are much more destructive than traditional explosives because nu</span><span>clear reactions can release much more energy than chemical reactions. Hope this answers the question.</span>
vazorg [7]4 years ago
4 0

Answer: The correct answer is option D.

Explanation:

Chemical reactions are defined as the reactions in which rearrangement of one or more substances gets converted to one or more different substances known as products. Energy is released in the reactions where energy of products is less than the energy of the reactants.

Nuclear reactions are the reactions in which atomic nucleus undergoes change and releases a huge amount of energy in the process. There are two types of nuclear reactions: Nuclear fusion and nuclear fission. Both the nuclear reactions releases a huge amount of energy.

From the given information above, we conclude that the correct option is Option D.

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Complete question

A 2700 kg car accelerates from rest under the action of two forces. one is a forward force of 1157 newtons provided by traction between the wheels and the road. the other is a 902 newton resistive force due to various frictional forces. how far must the car travel for its speed to reach 3.6 meters per second? answer in units of meters.

Answer:

The car must travel 68.94 meters.

Explanation:

First, we are going to find the acceleration of the car using Newton's second Law:

\sum\overrightarrow{F}=m\overrightarrow{a} (1)

with m the mass , a the acceleration and \sum\overrightarrow{F} the net force forces that is:

(F-f) (2)

with F the force provided by traction and f the resistive force:

(2) on (1):

(F-f)=ma

solving for a:

a=\frac{F-f}{m} =\frac{1157N-902N}{2700kg} =0.094\frac{m}{s^{2}}

Now let's use the Galileo’s kinematic equation

Vf^{2}=Vo^{2}+2a\varDelta x (3)

With Vo te initial velocity that's zero because it started from rest, Vf the final velocity (3.6) and \varDelta x the time took to achieve that velocity, solving (3) for \varDelta x:

\varDelta x= \frac{Vf^{2}}{2a} = t= \frac{(3.6\frac{m}{s})^2}{2*0.094\frac{m}{s^{2}}}

t=68.94 m

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3 years ago
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