Just multiply the "1.0 m/s" by ' 1 ' a few times. (Remember that a fraction with the same quantity on top and bottom is equal to ' 1 ' .)
(1.0 m/sec) · (1 km/1000 m) · (60 sec/min) · (60 min/hr) =
(1.0 · 60 · 60 / 1,000) (m · km · sec · min / sec · m · min · hr) =
(3,600 / 1,000) (km / hr) =
3.6 km/hr .
The answer is already in the blank for, its was greater
Answer:
The magnitude of the car's acceleration as it slows during braking is 36.81 m/s²
Explanation:
From the question, the given values are as follows:
Initial velocity, u = 90 m/s
final velocity, v = 0 m/s
distance, s = 110 m
acceleration, a = ?
Using the equation of motion, v² = u² + 2as
(90)² + 2 * 110 * a = 0
8100 + 220a = 0
220a = -8100
a = -8100/220
a = -36.81 m/s²
The value for acceleration is negative showing that car is decelerating to a stop. The magnitude of the car's acceleration as it slows during braking is therefore 36.81 m/s²
Answer:
Explanation:
Given the following data;
Mass of child = 23 kg
Mass of bike = 5.5 kg
Velocity = 4.5 m/s
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
To find the momentum of each of them;
I. Momentum of the child
Momentum C = mass * velocity
Momentum C = 23 * 4.5
Momentum C = 103.5 Kgm/s
II. Momentum of the bike
Momentum B = mass * velocity
Momentum B = 5.5 * 4.5
Momentum B = 24.75 Kgm/s
Hence, we can deduce from the calculations that the momentum of the child is greater than that of the bike because of the higher mass possessed by the child.
Answer:
v = -0.45 m/s
Explanation:
Assuming the canoe was initially at rest with momentum L = 0
and that the dog's velocity is in the positive direction
conservation of momentum
0 = 15(1.2) + 40v
v = -0.45 m/s