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jonny [76]
4 years ago
14

Traditional explosives use the energy released by chemical reactions. Nuclear weapons use the energy released by nuclear reactio

ns. Why are nuclear weapons much more destructive than traditional explosives? Question 16 options: A. Chemical reactions can release much more energy than nuclear reactions B. Chemical reactions always use more energy than they release Nuclear weapons always contain more chemicals than traditional explosive C. Chemical reactions always release more energy than they use D. Nuclear reactions can release much more energy than chemical reactions
Physics
2 answers:
lawyer [7]4 years ago
5 0
I believe the correct answer from the choices listed above is option D. Nu<span>clear weapons are much more destructive than traditional explosives because nu</span><span>clear reactions can release much more energy than chemical reactions. Hope this answers the question.</span>
vazorg [7]4 years ago
4 0

Answer: The correct answer is option D.

Explanation:

Chemical reactions are defined as the reactions in which rearrangement of one or more substances gets converted to one or more different substances known as products. Energy is released in the reactions where energy of products is less than the energy of the reactants.

Nuclear reactions are the reactions in which atomic nucleus undergoes change and releases a huge amount of energy in the process. There are two types of nuclear reactions: Nuclear fusion and nuclear fission. Both the nuclear reactions releases a huge amount of energy.

From the given information above, we conclude that the correct option is Option D.

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[03.02]
Yuki888 [10]

Answer:

in other to gain more power you would need to increase either current or voltage

Explanation:

In other to gain more power, you would need to increase either current or voltage,because power is directly proportional to voltage when current is kept constant.also power is directly proportional to current when voltage is kept constant

4 0
3 years ago
Heater supplies 80 J of energy to a block of metal. The temperature of the block rises by 20 °C.
Grace [21]

Answer:

Its internal energy decreases by 40 J.

Explanation:

The energy supplied to the metal block causes the temperature of the block to rise. Therefore,

Heat\ Supplied = mC\Delta T\\80\ J = mC(20^oC)\\mC = 4\ J/^oC\\

Now, we will use this value of mC to find out the energy change of block:

Energy\ Change = mC\Delta T\\Energy\ Change = (4\ J/^oC)(-10^oC)\\Energy\ Change = -40J\\

It shows that when the temperature of the metal block falls by 10°C,

<u>Its internal energy decreases by 40 J.</u>

5 0
3 years ago
PLS ANSWER ASAP
vivado [14]

Answer:

Cart A

Explanation:

Momentum can be computed by finding the product of mass and velocity. To solve this, you can use the formula below to find the greatest momentum:

p = mv

where:

p = momentum (kgm/s)       m = mass (kg)         v = velocity (m/s)

Because carts are moving along with the weights, we need to consider the whole system. This means that you need to add in the masses and the mass of the cart.

<u>Cart A:</u>

m = 200kg + 0 kg = 200 kg

v = 4.8 m/s

p = 200kg x 4.8 m/s = 960 kg-m/s

<u>Cart B:</u>

m = 200kg + 20 kg = 220 kg

v = 4.0 m/s

p = 220kg x 4.0 m/s = 880 kg-m/s

<u>Cart C:</u>

m = 200kg + 40 kg = 240 kg

v = 3.8 m/s

p = 240kg x 3.8 m/s = 912 kg-m/s

<u>Cart D:</u>

m = 200kg + 60 kg = 260 kg

v = 3.5 m/s

p = 260kg x 3.5 m/s = 910 kg-m/s

As you can see, Cart A has the greatest momentum.

5 0
3 years ago
Read 2 more answers
Are ultrasound waves high energy waves or low energy waves?
german
And think they are high energy waves. But I'm not sure
3 0
4 years ago
Calculate the work required to move a planet’s satellite of mass 571 kg from a circular orbit of radius 2R to one of radius 3R,
Marrrta [24]

Answer:

5.6 x 10^9 J

Explanation:

mass of satellite, m = 571 kg

r1 = 2 R

r2 = 3R

R = 8.8 x 10^6 m

mass of planet, M = 7.76 x 10^24 kg

The formula for the work done is given by

W=GMm\left ( \frac{1}{r_{1}}-\frac{1}{r_{2}} \right )

Where, G is universal gravitational constant, G = 6.67 x 10^-11 Nm^2/kg^2

W=GMm\left ( \frac{1}{2R}-\frac{1}{3R} \right )=\frac{GMm}{6R}

W=\frac{6.67\times10^{-11}\times7.76\times10^{24}\times 571}{6\times 8.8\times10^6}

W = 5.6 x 10^9 J

4 0
3 years ago
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