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3 years ago

How to calculate this ? Do you use the molar mass and multiply it by the mass given ?

Chemistry

1 answer:

AveGali [126]3 years ago

4 0

Answer:

Option C. 8.91g

Explanation:

The balanced equation for the reaction is given below:

2Pb(NO3)2 —> 2PbO + 4NO2 + O2

Next, we shall determine the mass of Pb(NO3)2 that decomposed and the mass PbO produced from the balanced equation.

This is illustrated below below:

Molar mass of Pb(NO3)2 = 207 + 2[14 + (16x3)]

= 207 + 2[14 + 48]

= 207 + 2[62] = 207 + 124

= 331g/mol

Mass of Pb(NO3)2 from the balanced equation = 2 x 331 = 662g

Molar mass of PbO = 207 + 16 = 223g/mol

Mass of PbO from the balanced equation = 2 x 223 = 446g

Summary:

From the balanced equation above,

662g of Pb(NO3)2 decomposed to produce 446g of PbO.

Finally, we can obtain the maximum mass of lead(II) oxide, PbO produced from 13.23g of lead (II) nitrate, Pb(NO3)2 as follow:

From the balanced equation above,

662g of Pb(NO3)2 decomposed to produce 446g of PbO.

Therefore, 13.23g of Pb(NO3)2 will decompose to produce = (13.23 x 446)/662 = 8.91g of PbO.

Therefore, 8.91g of PbO were obtained from the decomposition of 13.23g of Pb(NO3)2

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How many grams of iron metal do you expect to be produced when 245 grams of an 80.5 percent by mass iron (II) nitrate solution r

NNADVOKAT [17]

2Al + 3Fe(NO₃)₂ = 3Fe + 2Al(NO₃)₃

m=245 g
w=0.805 (80.5%)
M{Fe(NO₃)₂}=179.857 g/mol
M(Fe)=55.847 g/mol

1. the mass of salt in solution is:
m{Fe(NO₃)₂}=mw

2. the proportion follows from the equation of reaction:
m(Fe)/3M(Fe)=m{Fe(NO₃)₂}/3M{Fe(NO₃)₂}

m(Fe)=M(Fe)m{Fe(NO₃)₂}/M{Fe(NO₃)₂}

m(Fe)=M(Fe)mw/M{Fe(NO₃)₂}

m(Fe)=55.847*245*0.805/179.857= 61.24 g

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3 years ago

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Answer:

c) H2O and OH−

Explanation:

Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.

When an acid donates a proton, it changes into a base which is known as its conjugate base.

Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.

The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.

Thus, for the reaction,

$NH_3+H_2O\rightleftharpoons Nh_4^++OH^-$

The base is $NH_3$ and the conjugate acid of the base is $NH_4^+$ .

Also, The base is $OH^-$ and the conjugate acid of the base is $H_2O$ .

<u>Correct option is :- c) H2O and OH−</u>

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3 years ago

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Of course, on reaction with sodium, the sodium reduces the chlorine molecule to give 2×Cl−. The resultant bond between Na+ and Cl−is ionic and a non-molecular substance results.

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