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motikmotik
3 years ago
10

The electric field 14.0 cm from the surface of a copper ball of radius 2.0 cm is directed toward the ball's center and has magni

tude 9.0 ✕ 10^2 N/C. How much charge is on the surface of the ball (in C)? (Include the sign of the value in your answer.)
Physics
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

Q = - 256 X 10⁻⁷ C .

Explanation:

Electric field due to a charge Q at a distance d from the center is given by the expression

E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹

Put the given value in the equation

9 x 10² = \frac{9\times10^9\times Q}{(14+2)^2\times10^{-4}}

Q = \frac{9\times16^2\times10^{-2}}{9\times10^9}

Q = - 256 X 10⁻⁷ C .

It will be negative in nature as the field is directed towards the center.

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Answer:

mass.

Explanation:

other physical factors are changeable but the mass of a particular substance is always constant.

6 0
3 years ago
Take a look at the weather map. The front seen there causes short periods of storms and heavy rains. What type of front is this?
erastova [34]
I am pretty sure it is a cold front.
5 0
3 years ago
Read 2 more answers
A light ray incident on a block of glass makes an incident angle of 50.0° with the normal to the surface. The refracted ray in t
Vladimir [108]

Answer:

The index of refraction of the glass is 1.3

Explanation:

Given data:

i = incident angle = 50°

r = refracted angle = 36.1°

The index of refraction according Snell´s law is:

n=\frac{1*sini}{sinr} =\frac{1*sin50}{sin36.1} =1.3

4 0
3 years ago
a ball is thrown striaght up in the air and then falls back to earth. if the downward fall takes 2.2s, how fast is the ball trav
lapo4ka [179]

The velocity of the ball when it strikes the ground, given the data is 21.56 m/s

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Time to reach ground from maximum height (t) = 2.2 s
  • Initial velocity (u) = 0 m/s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Final velocity (v) =?

<h3>How to determine the velocity when the ball strikes the ground</h3>

The velocity of the ball when it strikes the ground can be obtained as illustrated below:

v = u + gt

v = 0 + (9.8 × 2.2)

v = 0 + 21.56

v = 21.56 m/s

Thus, the velocity of the ball when it strikes the ground is 21.56 m/s

Learn more about motion under gravity:

brainly.com/question/22719691

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5 0
1 year ago
Plane a travels at 900km/h and plane b travels at 250/5.which plane travels faster
vesna_86 [32]

Explanation:

We have,

Speed of plane a is 900 km/h

Plane b is moving at a rate of \dfrac{250\ km}{5\ h}=50\ km/h

It is required to find which plane is faster. To find which plane is faster, we need to compare their speeds.

Speed of a plane a is 900 km/h and that of plane b is 50 km/h. So, we can say that plane a is moving faster.

5 0
3 years ago
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