Answer:
True
Explanation:
If a thin, spherical, conducting shell carries a negative charge, We expect the excess electrons to mutually repel one another, and, thereby, become uniformly distributed over the surface of the shell. The electric field-lines produced outside such a charge distribution point towards the surface of the conductor, and end on the excess electrons. Moreover, the field-lines are normal to the surface of the conductor. This must be the case, otherwise the electric field would have a component parallel to the conducting surface. Since the excess electrons are free to move through the conductor, any parallel component of the field would cause a redistribution of the charges on the shell. This process will only cease when the parallel component has been reduced to zero over the whole surface of the shell
According to Gauss law
∅ = EA =-Q/∈₀
Where ∅ is the electric flux through the gaussian surface and E is the electric field strength
If the gaussian surface encloses no charge, since all of the charge lies on the shell, so it follows from Gauss' law, and symmetry, that the electric field inside the shell is zero. In fact, the electric field inside any closed hollow conductor is zero
Answer:
- 1.3 x 10⁻¹⁵ C/m
Explanation:
Q = Total charge on the circular arc = - 353 e = - 353 (1.6 x 10⁻¹⁹) C = - 564.8 x 10⁻¹⁹ C
r = Radius of the arc = 5.30 cm = 0.053 m
θ = Angle subtended by the arc = 48° deg = 48 x 0.0175 rad = 0.84 rad (Since 1 deg = 0.0175 rad)
L = length of the arc
length of the arc is given as
L = r θ
L = (0.053) (0.84)
L = 0.045 m
λ = Linear charge density
Linear charge density is given as
Inserting the values
λ = - 1.3 x 10⁻¹⁵ C/m
In the test, it is observed that water that is not too deep If carbon dioxide levels are not low enough, blackout causes elevation.
<h3>What is research?</h3>
Unique and methodical activity performed to improve the reservoir of knowledge is known as the research. . A research project might be a continuation of previous work in the topic.
By the following way, the test is conducted;
1. The effect of the conversation test on exercise intensity prescription and monitoring in competitive athletes. The sound of your breath might assist you figure out what's wrong.
Athletes require oxygen to give energy and to eliminate carbon dioxide, which is a waste product produced when energy is produced.Because it is a reliable indicator of ventilatory efficiency in cardiac patients.
Ventilatory threshold performance is used to determine the lactate threshold. The maximal rate of oxygen consumption recorded during activity is 5.VO2 max. It is higher in trained people than in unskilled people.
Hence,in the test it is observed that water that is not too deep If carbon dioxide levels are not low enough, blackout causes elevation.
To learn more about the research, refer to the link;
brainly.com/question/18723483
#SPJ1
Answer:
f1/f2 =W1/W2 = 1/3
.0 f2 = 3f1
As ,
1/F= 1/f1 +1/f2
...1/40 = 1/f1 - 1/3f1
f1=> 80/3 cm
... f2 = 2f1 = 3 x 80/3 = 80 cm
Answer:
B
Explanation:
Atomic structure contains electrons, protons and neutrons.
Electron is very light compared to proton and neutrons.
Given that the mass of an electron is
A) equal to the mass of a proton
B) less than the mass of a neutron
C) greater than the mass of a proton
D) equal to the mass of a neutron
The correct answer is B which is less than the mass of the neurons.