Answer:
Infrared photons carry lower radiation energy than the visible light.
Explanation:
- Each photon carries an energy that is directly proportional to its frequency, being this proportionality constant the Planck's constant h.
- So, we can write the energy of a single photon as follows:
- Since there exists an inverse relationship between wavelength and frequency, and infrared radiation has longer wavelengths, this means that its frequency is lower than the one of the visible light.
- So, an infrared photon carries less energy that one of the visible light.
I’ve answered this problem before and there were 2 parts in
this problem.
The solution would be like this for this specific problem:
<span>A.
</span><span>Vf = Vi +
Vex*ln(Mi / Mf) </span><span>
<span>0.002 * 3e8m/s = 0 + 2000m/s * ln(Mi / Mf) </span>
<span>300 = ln(Mi / Mf) </span>
<span>1.9e130 = Mi / Mf </span></span>
<span>B.
</span><span>4000m/s =
2000m/s * ln(Mi / Mf) </span><span>
<span>2 = ln(Mi / Mf) </span>
<span>7.389 = Mi / Mf </span>
<span>Mf = Mi / 7.389 = 0.135*Mi<span> </span></span></span>
Answer:
Opposite to the net force
Explanation:
The frictional force is a constant force that resists the motion of a body.
There are two classifications of frictional force
1) Static friction
2) Kinetic friction
When a force acts on two surfaces that prevent the sliding between them is the static frictional force.
When a force acts on a moving surface that opposes the motion of the surface is called the kinetic friction.
<em>The kinetic frictional force acts in the direction opposite to the motion and the net force.
</em>
The static and kinetic frictions are dimensionally the same quantity only the coefficient of the friction is higher for static friction.
