A generic solid, X, has a molar mass of 60.2 g/mol. In a constant‑pressure calorimeter, 34.1 g of X is dissolved in 283 g of wat
er at 23.00 °C. X ( s ) ⟶ X ( aq ) The temperature of the resulting solution rises to 27.30 °C. Assume the solution has the same specific heat as water, 4.184 J/(g·°C), and that there is negligible heat loss to the surroundings. How much heat was absorbed by the solution?
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Answer:
Explanation:
Expression for relative velocity
=
= (.54 + .82 )c/
= 1.36 c / 1.4428
= .94 c
β = .94