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pickupchik [31]
3 years ago
6

A- 1000 m/s2 Xi-0m Xf-0.75m Vf-?

Physics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

The final velocity of the object is,  v_{f} = 27 m/s    

Explanation:

Given,

The acceleration of the object, a = 1000 m/s²

The initial displacement of the object, x_{i} = 0 m

The final displacement of the object,  x_{f} = 0.75 m

The initial velocity of the object will be, v_{i} = o m/s

The final velocity of the object, v_{f} = ?

The average velocity of the object,

                                    v = ( x_{f} - x_{i} )/ t

                                      = 0.75 / t

The acceleration is given by the relation

                                     a = v / t

                                   1000 m/s² = 0.75 / t²

                                            t² = 7.5 x 10⁻⁴

                                            t = 0.027 s

Using the I equation of motion,

                                  v_{f} = u + at

Substituting the values

                                   v_{f} = 0 + 1000 x 0.027

                                                           = 27 m/s

Hence, the final velocity of the object is,  v_{f} = 27 m/s          

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Compute the density in g/cm? of a piece of metal that has a mass of 0.450 kg and a volume of 52 cm3
Y_Kistochka [10]

Answer:

Ro = 8.65 [g/cm³]

Explanation:

We must remember that density is defined as the ratio of mass to volume.

Ro=m/V

where:

m = mass = 0.450 [kg] = 450 [g]

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Ro = density [g/cm³]

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8 0
2 years ago
Two blocks of clay, one of mass 1.00 kg and one of mass 7.00 kg, undergo a completely inelastic collision. Before the collision
RideAnS [48]

Answer:8 m/s

Explanation:

Given

m_1=1 kg

m_2=7 kg

kinetic Energy of m_1=32 J

initially m_2 is at rest and let say m_1 is moving with velocity u

kinetic Energy of m_1 is =\frac{m_1u^2}{2}=32

u^2=64

u=8 m/s

In Completely inelastic collision both mass stick together and move with common velocity

Suppose v is the common velocity

m_1u+0=(m_1+m_2)v

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3 years ago
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ankoles [38]

Answer:

u = - 38.85 m/s^-1

Explanation:

given data:

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time = 1.85*10^{-3} s

final velocity = 0 m/s

from equation of motion we have following relation

v = u +at

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0 = u + 38.85

u = - 38.85 m/s^-1

negative sign indicate that the ball bounce in opposite directon

4 0
3 years ago
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