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vodomira [7]
3 years ago
10

What is the wavelength of a wave traveling with a wave speed of 1348 m/s

Physics
1 answer:
saw5 [17]3 years ago
5 0

Answer:    f = 4 Hz i think

Explanation:

sorry i dont rember (cant type lol)

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Calculate the pressure of water in a will if the deep of the water is 10 m​
Bas_tet [7]

Answer:

98,000 pa

Explanation:

The formula for water pressure is as follows:

pressure = pgh

Where <em>p </em>is the density of water (in kg/m3), <em>g </em>is the gravitational field strength, and <em>h </em>is the height of the water.

The density of water is 1000kg/m3, the gravitational field strength is 9.8, and the height is 10. Substituting in these values:

pressure = 1000 \times 9.8 \times 10

pressure = 98000

7 0
2 years ago
In your experiment, you measure a total deflection of 4.12 cm when an electric field of 1.10×103V/m is established between the p
Bond [772]

Answer:

B_0 = 1.69 \times 10^{-4}\ T

Explanation:

given,

total deflection = 4.12 cm

Electric field = 1.1 ×10³ V/m

plate length = 6 cm

distance between them = 12 cm

using formula

v_0 = \sqrt{\dfrac{q\epsilon_0d}{ym}(\dfrac{d}{2}+L)}

q = 1.6 × 10⁻¹⁹ C

m = 9.11 x 10⁻³¹ kg

d = 0.06 m

L = 0.12 m

v_0 = \sqrt{\dfrac{1.6 \times 10^{-19}\times 1.1 \times 10^{3}\times 0.06}{0.0412\times 9.11 \times 10^{-31} }(\dfrac{0.06}{2}+0.12)}

v_0 = 6496355.63 m/s

v_0 = \dfrac{E}{B_0}

B_0 = \dfrac{E}{v_0}

B_0 = \dfrac{1.1\times 10^{3}}{6496355.63}

B_0 = 1.69 \times 10^{-4}\ T

5 0
3 years ago
HELP PLEASE <br> THANK YOU!!
Simora [160]
Kelvin is the answer
4 0
3 years ago
Read 2 more answers
If the lily pads are spaced 2.4 m apart and Ferdinand jumps with a speed of 5 m/s taking 0.6 s to go from lily pad to lily pad,
Zina [86]

Answer:

36.87^{\circ}

Explanation:

v = Velocity of Ferdinand = 5 m/s

\theta = Angle of jump

T = Time taken = 0.6 s

R = Distance between lily pads = 2.4 m

Horizontal range is given by

R=v_xT\\\Rightarrow R=vcos\theta T\\\Rightarrow cos\theta=\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{2.4}{5\times 0.6}\\\Rightarrow \theta=36.87^{\circ}

The angle at which Ferdinand make each of his jumps is 36.87^{\circ}

8 0
3 years ago
Can someone help me?!!!!!
german
<h2>Hello!</h2>

The answer is:

The first option,  the walker traveled 360m more than the actual distance between the start and the end points.

Why?

Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).

So, calculating we have:

Traveler:

Distance=NorthCoveredDistance+EastCoveredDistance

Distance=4*180m+3*180m=720m+540m=1260m

Actual distance between the start and the end point (displacement):

ActualDistance=\sqrt{NorthDistance+EastDistance}\\\\ActualDistance=\sqrt{NorthDistance^{2} +EastDistance^{2}}\\\\ActualDistance=\sqrt{(720m)^{2} +(540m)^{2}}\\\\ActualDistance=\sqrt{518400m^{2} +291600m^{2}}\\\\ActualDistance=\sqrt{810000m^{2}}=900m

Now, to calculate how much farter did the traveler walk, we need to use the following equation:

DistanceDifference=WalkerCoveredDistance-ActualDistance\\\\DistanceDifference=1260m-900m=360m

Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.

Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.

Have a nice day!

3 0
3 years ago
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