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vodomira [7]
3 years ago
10

What is the wavelength of a wave traveling with a wave speed of 1348 m/s

Physics
1 answer:
saw5 [17]3 years ago
5 0

Answer:    f = 4 Hz i think

Explanation:

sorry i dont rember (cant type lol)

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Integrated Science- 8th grade science
mart [117]

Answer:

"Why"

Explanation: A scientific law is a description of how the natural world behaves under certain circumstances.

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3 years ago
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Which of the following is accurate in describing converging and diverging lenses?
kenny6666 [7]

B. Both of these types of lenses have the ability to produce real images.

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3 years ago
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what are three activities in your everyday life that involve electromagnetic energy? and explain what type of electromagnetic en
mihalych1998 [28]

1). While I'm driving the car, I keep my eyes pointed out the front window,

so that LIGHT WAVES coming straight in through the front window get into

them. Using this process, I'm able to SEE what's in front of me, so that I don't

drive straight into it.


2). Also while I'm driving the car, I usually have the radio on, and I tune it

to a frequency where the RADIO WAVES that it responds to are being

modulated by people who are either talking or else playing classical music.


3). Before I leave the house on most days, I take a small container of

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in some way with MICROWAVE energy, since I work as a microwave

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8 0
3 years ago
All of the following are factors affecting flow rate except what?
faust18 [17]

Answer:

c. Vessel side holes

Explanation:

  • The "Poiseuille formula" which is given by \\\begin{aligned} \small Q& =  \small \frac{\pi r^4}{8 \eta}.\frac{\Delta P}{\Delta L}\\\end{aligned} describes the volumetric flow rate (\small Q) through tubular sections.
  • Here, \Delta P,\,\, \Delta L,\,\, r,\,\, \eta represent the injection pressure difference, the length of the section, the radius of the section and the viscosity index of the fluid that flows through the section respectively.
  • With this, one can confirm that all the factors except the vessel side holes affect the flow rate.
  • Side holes, however, are a factor that could give a measure of how much volume would flow to a particular location. In such a situation the flow rate remains unchanged and one location would receive a lower volume (not the whole) as some volume would spill out at the side holes.

#SPJ4

5 0
2 years ago
What is the force required to produce a 1.4 Nm torque when applied to a door at a 60.0º angle and 0.40 m from the hinge?
Marysya12 [62]
Refer to the diagram shown below.

The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N

Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m

This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N

Answer: 4.04 N

5 0
3 years ago
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