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3 years ago

8

The magnitude of the net force versus time graph has a rectangular shape. Often in physics geometric properties of graphs have p

hysical meaning. True or false

1 answer:

Blizzard [7]3 years ago

8 0

Answer:

True

Explanation:

In this particular case, the area of the graph represents the impulse.

In fact, impulse is defined as the change in momentum of an object:

$I=\Delta p$

Moreover, impulse is also defined as the product between the magnitude of the force acting on an object and the duration of the collision:

$I=F\Delta t$

If we plot a graph of the force versus the time, if the force is constant then this graph will have a rectangular shape, and the area under the graph will simply be the product

$F\cdot \Delta t$

which corresponds to the definition of impulse.

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The electron dot diagram shows the arrangement of dots without identifying the element.

olasank [31]

<em>Answer: </em>tellurium (Te)

<em>atomic number = 52 ,</em>

<em>Number of energy levels = 5;</em>

First energy level = 2

Second energy level = 8

Third energy level = 18

Fourth energy level = 18

Fifth energy level = 6

<em>In this electron configuration, 0uter most electrons are 6.</em>

5 0

3 years ago

Read 2 more answers

if the mass of the objects stays the same and their distance from eachother decreases, then the force of gravity between the two

dedylja [7]

Then the force of gravity between them would be quadrupled and so on but the gravitational force is inversely proportional to the square of the separation distance between the two interacting objects which makes more separation distance will result in weaker gravitational forces

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1 year ago

A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3

shusha [124]

Answer:

a

$x_2 = -2.3356$

b

$v = -1.384 \ m/s$

Explanation:

From the question we are told that

The initial position of the particle is $x_1 = 0.180 \ m$

The initial velocity of the particle is $u = 0.060 \ m/s$

The acceleration is $a = -0.380 \ m/s^2$

The time duration is $t = 3.80 \ s$

Generally from kinematic equation

$v = u + at$

=> $v = 0.060 + (-0.380 * 3.80)$

=> $v = -1.384 \ m/s$

Generally from kinematic equation

$v^2 = u^2 + 2as$

Here s is the distance covered by the particle, so

$(-1.384)^2 = (0.060)^2 + 2(-0.380)* s$

=> $s = -2.5156 \ m$

Generally the final position of the particle is

$x_2 = x_1 + s$

=> $x_2 = 0.180 + (-2.5156)$

=> $x_2 = -2.3356$

6 0

3 years ago

A phone cord is 4.89 m long. The cord has a mass of 0.212 kg. A transverse wave pulse is produced by plucking one end of the tau

slega [8]

Answer:

Tension in Cord=174 N

Explanation:

Given Data

L (Phone Cord Length)=4.89 m

m (Cord Mass)=0.212 Kg

T (Time for four trips)=0.617 s

Tension=?

Solution

V=λ×f

$V=\frac{8*4.89}{0.617}\\ V=63.4m/s$

$Sigma=\frac{mass}{length}\\ Sigma=\frac{0.212}{4.89}\\ Sigma=0.0433 \frac{kg}{m}$

$Wave Speed=\sqrt{\frac{Tension}{Sigma} }\\ \\V=\sqrt{\frac{T}{Sigma} }\\ V^{2}=\frac{T}{Sigma}\\ T=V^{2}*Sigma\\ T=(63.4)^{2}*(0.0433)\\ T=174 N$

5 0

3 years ago

A 19 kg child is riding a 5.6 kg bike with a

icang [17]

Answer:

$\mathrm{a.\:}123\:\mathrm{kg\cdot m/s},\\\mathrm{b.\:}95\:\mathrm{kg\cdot m/s},\\\mathrm{c.\:}28\:\mathrm{kg\cdot m/s}$

Explanation:

The momentum of an object is given by:

$p=mv$ , where $m$ is the mass of the object and $v$ is the velocity of the object.

a)

The mass of the child and bike together is $19+5.6=24.6$ kilograms. Since they're moving at a velocity of 5.0 m/s, their momentum is:

$p=24.6\cdot 5=\fbox{$123\:\mathrm{kg\cdot m/s}$}$ .

b)

The mass of the child is given as 19 kg. Since the child is on the bike moving at 5.0 m/s, it's implied the child is as well. Therefore, the momentum of the child is:

$p=19\cdot 5=\fbox{$95\:\mathrm{kg\cdot m/s}$}$ .

c) The mass of the bike is given as 5.6 kg and it is moving at 5.0 m/s. Therefore, the momentum of the bike is:

<u /> $p=5.6\cdot 5=\fbox{$28\:\mathrm{kg\cdot m/s}$}$ <u />

4 0

3 years ago