Answer:
![\Delta V = 1.8 \times 10^7 V](https://tex.z-dn.net/?f=%5CDelta%20V%20%20%20%20%3D%201.8%20%5Ctimes%2010%5E7%20V)
Explanation:
GIVEN
diameter = 15 fm =
m
we use here energy conservation
![K_{i}+U_{i} =K_{f}+U_{f}](https://tex.z-dn.net/?f=K_%7Bi%7D%2BU_%7Bi%7D%20%3DK_%7Bf%7D%2BU_%7Bf%7D)
there will be some initial kinetic energy but after collision kinetic energy will zero
![K_{i} + 0 = 0 + \frac{1}{4 \pi \epsilon _{0}} \frac{(2e)(92e)}{7.5 \times 10^{-15}}](https://tex.z-dn.net/?f=K_%7Bi%7D%20%2B%200%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cepsilon%20_%7B0%7D%7D%20%5Cfrac%7B%282e%29%2892e%29%7D%7B7.5%20%5Ctimes%2010%5E%7B-15%7D%7D)
on solving these equations we get kinetic energy initial
J ..............(i)
That is, the alpha particle must be fired with 35.33 MeV of kinetic energy. An alpha particle with charge q = 2 e
and gains kinetic energy K =e∆V ..........(ii)
by accelerating through a potential difference ∆V
Thus the alpha particle will
just reach the
nucleus after being accelerated through a potential difference ∆V
equating (i) and second equation we get
e∆V = 35.33 Me V
![\Delta V = \frac{35.33}{2} MV\\\Delta V = 1.8 \times 10^7 V](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20%5Cfrac%7B35.33%7D%7B2%7D%20%20MV%5C%5C%5CDelta%20V%20%20%20%20%3D%201.8%20%5Ctimes%2010%5E7%20V)
Answer:
Force that acted on the body was F = 13 N
Explanation:
If once accelerated, the body covers 60 meters in 6 seconds, then its velocity is 60/6 m/s = 10 m/s
When the force was acting (for 10 seconds) the object accelerated from rest (initial velocity vi = 0) to 10 m/s (its final velocity). therefore we can use the kinematic equation for the velocity in an accelerated motion given by:
![v_f=v_i+a*t](https://tex.z-dn.net/?f=v_f%3Dv_i%2Ba%2At)
which in our case becomes;
![10\,m/s=0+a*(10\,s)](https://tex.z-dn.net/?f=10%5C%2Cm%2Fs%3D0%2Ba%2A%2810%5C%2Cs%29)
and we can solve for the acceleration as:
a = 10/10 m/s^2 = 1 m/s^2
Therefore the force acting on the body, based on Newton's 2nd Law expression: F = m * a is:
F = 13 kg * 1 m/s^2 = 13 N
Answer:
(a) 3.44 x 10^-3 m^3/s
(b) 8.4 m/s
Explanation:
area of water line, A = 5.29 x 10^-3 m
number of holes, N = 15
Speed of water in line, V = 0.651 m/s
(a) Volume flow rate is given by
V = area of water line x speed of water in water line
V = 5.29 x 10^-3 x 0.651 = 3.44 x 10^-3 m^3/s
(b) area of one hole, a = 4.13 x 10^-4 m
Let v be the velocity of water in each hole
According to the equation of continuity
A x V = a x v
5.29 x 10^-3 x 0.651 = 4.1 x 10^-4 x v
v = 8.4 m/s
The tilt of the moon's axis does not allow for monthly alignment, so the lunar and solar eclipse do not happen every month.
<h3>How do the lunar and solar eclipse occur?</h3>
- For the occurrence of lunar and solar eclipse, the sun, moon and the earth must remain in a plan and along a straight line.
- When the earth appears in between the sun and the moon, lunar eclipse occurs.
- When the moon appears in between the sun and the earth, solar eclipse occurs.
- The moon and earth are rotating not only around the sun, but also around the black hole of Milky way galaxy.
- So they are not present in a plan as well as in a straight line in every full moon and new moon time.
Thus, we can conclude that the option D is correct.
Learn more about the lunar eclipse and solar eclipse here:
brainly.com/question/8643
#SPJ1
Answer:
the answer is OD which says tge buoyant girce on an object is equal to the weight of th fluid