Answer:The net force acting on the car is 3×103 Newtons
Explanation:
Answer:
Explanation:
check attached image for figure, there is supposed to be a figure for this question containing a distance(height of collar at position A) but i will assume 0.2m or 200mm
Consider the energy equilibrium of the system
Here, F is the force acting on the collar, is the height of the collar at position A, m is the mass of the collar C, g is the acceleration due to gravity, is the velocity of the collar at position B, and is the velocity of the collar at A
Substitute 14.4N for F, 0.2m for , 1.5kg for m, for g and 0 for
Therefore, the velocity at which the collar strikes the end B is 4.412m/s
Answer:
Final velocity of the block = 2.40 m/s east.
Explanation:
Here momentum is conserved.
Initial momentum = Final momentum
Mass of bullet = 0.0140 kg
Consider east as positive.
Initial velocity of bullet = 205 m/s
Mass of Block = 1.8 kg
Initial velocity of block = 0 m/s
Initial momentum = 0.014 x 205 + 1.8 x 0 = 2.87 kg m/s
Final velocity of bullet = -103 m/s
We need to find final velocity of the block( u )
Final momentum = 0.014 x -103+ 1.8 x u = -1.442 + 1.8 u
We have
2.87 = -1.442 + 1.8 u
u = 2.40 m/s
Final velocity of the block = 2.40 m/s east.
Some things that causes friction between surfaces is a bike on a rocky road. The<span> action of one surface or object rubbing against another causing friction. Im not really sure if I helped But yeah..</span>
Answer:
Explanation:
initial velocity, u = 8 m/s
vertical height, h = 1 m
θ = 40°
Let the horizontal distance is d and the time taken is t.
Use second equation of motion in vertical direction
h = ut + 1/2 at²
1 = 8 Sin 40 x t + 0.5 x 9.8 t²
1 = 5.14 t - 4.9t²
4.9t² - 5.14 t + 1 = 0
so, t = 0.26 s (smaller value)
So, the horizontal distance is
d = u cos 40 x t
d = 8 cos 40 x 0.26
d = 1.6 m