Answer:
coal tar is one of the product of coal
Direction of motion is one part of a complete description of velocity.
So if the direction of motion changes, that's a <em>change of velocity</em>, even if the speed didn't change.
The change of direction is called "an acceleration", even if the speed didn't change.
No, both the cars do not have the same velocity.
Velocity is a vector quantity and it is the rate of change of displacement with time or change in speed with direction.
Velocity has both magnitude and direction. So when you are in a car going 70 km/h and another car goes in the opposite direction at 70 km/h their velocities are different.
How?
Consider your car as moving in the positive direction, so its velocity will be 70 km/h and for the car moving in the opposite direction, since the direction is opposite, the velocity of that car will be -70 km/h. This is because, the velocity is a vector quantity that has both magnitude and direction. For one car, the direction is positive and for the other one the direction is negative.
Answer:
S = 12757.5 m
Explanation:
A magnitude of the displacement can be obtained by visualizing the walking. The actual path from A to B Is 3 m then from B to D as 5 m and finally from D to E as 6 m. |S| =√92+52 = 10.29 m. The direction of Resultant displacement is South East.
<u>Solving for the different variables we can use the following formulas: </u>
- Given v, u, and t solve for s
Given initial velocity, final velocity, and time calculate the displacement.
s = ½( v + u )t
- Given S, T, and U solve for V
Given displacement, time, and initial velocity calculate the final velocity.
v = 2s/t - u
- Given S, T, and V solve for U
Given displacement, time, and final velocity calculate the initial velocity.
u = 2s/t - v
- Given v, u, and t solve for s
Given initial velocity, final velocity, and time calculate the displacement.
t = 2s/ ( v + u )
Answer:
8.333*10^-6 ohms
Explanation:
Resistivity of a material is expressed as;
p = RA/l
R is the resistance of the material
A is the cross sectional area
l is the length of the material
Given
R = 5 ohms
A = 0.5mm^2
A = 5 * 10^-7m^2
l = 30cm = 0.3m
Substitute into the formula;
p = (5 * 5 * 10^-7m^2)/0.3
p = 25 * 10^-7/0.3
p = 0.0000025/0.3
p = 8.333*10^-6
Hence its resistivity at 20 degrees Celsius is 8.333*10^-6 ohms
