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Mkey [24]
3 years ago
14

Which of these experiments would make use of qualitative data?

Chemistry
1 answer:
marysya [2.9K]3 years ago
5 0

Answer:

B - A study of different surfaces to compare luster or shine.

Hope This Helps!

Have A Great Day :D

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Suppose that some FeSCN2+ is added to the above solution to shift the equilibrium. When equilibrium is re-established, the follo
kiruha [24]

Explanation:

The given reaction equation will be as follows.

          [FeSCN^{2+}] \rightleftharpoons [Fe^{3+}] + [SCN^{-}]

Let is assume that at equilibrium the concentrations of given species are as follows.

        [Fe^{3+}] = 8.17 \times 10^{-3} M

        [SCN^{-}] = 8.60 \times 10^{-3} M

        [FeSCN^{2+}] = 6.25 \times 10^{-2} M

Now, first calculate the value of K_{eq} as follows.

     K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}

              = \frac{8.17 \times 10^{-3} \times 8.60 \times 10^{-3}}{6.25 \times 10^{-2}}

              = 11.24 \times 10^{-4}

Now, according to the concentration values at the re-established equilibrium the value for [FeSCN^{2+}] will be calculated as follows.

             K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}

        11.24 \times 10^{-4} = \frac{8.12 \times 10^{-3} \times 7.84 \times 10^{-3}}{[FeSCN^{2+}]}

         [FeSCN^{2+}] = 5.66 \times 10^{-2} M

Thus, we can conclude that the concentration of [FeSCN^{2+}] in the new equilibrium mixture is 5.66 \times 10^{-2} M.

7 0
3 years ago
A plane flew for 2 hours at 467 mph (mile per hour)and 5 hours at 536 mph. How far did the plane fly miles?
Andreyy89

Answer:

the plane flew 3614 miles

7 0
3 years ago
4.One rubber tire can generate about250,000 BTUS (1BTU=.0003KW ) when it is burned. The average American home consumes about 10,
jekas [21]

Answer:

The number of tires required to power ten homes for one year is approximately 2,730 tires

Explanation:

The given information are;

The energy generated by burning one rubber tire = 250,000 BTUs

1 BTU = 0.0003 kW

The amount of energy consumed by the average American home = 10,000 kWh

Therefore, the amount of energy generated by burning one tire in kW can be found as follows;

The energy generated by burning one rubber tire = 250,000 BTUs

1 BTU = 0.0003 kW

∴ 1 BTU × 250,000 = 250,000 BTUs = 0.0003 kW × 250,000 = 75 kW

We note that 250,000 BTUs is equivalent to 263764 kJ

1 kWh is equivalent to 3600 kJ

10,000 kWh = 10,000 × 3600 = 36,000,000 kJ

The energy requirement for ten homes  for one year = 10 × 36,000,000 kJ = 360,000,000 kJ

At 50% efficiency, the energy produced per tire = 0.5 × 263764 kJ = 131,882 kJ

The electrical energy produced per tire = 131,882 kJ/tire

The number of tires required to power ten homes for one year = 360,000,000 kJ/  131,882 kJ/tire = 2,729.71293  ≈2,730 tires

The number of tires required to power ten homes  ≈2,730 tires.

8 0
3 years ago
What are three ways that magma can form
ankoles [38]
<span>The three ways magma can form are when rock is heated, when pressure is released, and when the composition of the rock changes. The temperature of magma is 1300-2400F. Magma collects in magma chambers under the earth's surface, and can be come to the surface in the form of lava.</span>
3 0
3 years ago
Julie finds a snail on the sidewalk and wants to know whether or not the snail moves throughout the day. She places a
AURORKA [14]
Acting as a reference point for detecting motion
3 0
3 years ago
Read 2 more answers
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