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Alex_Xolod [135]
3 years ago
5

Identify two macroscopic characteristics of water that are a result of its molecular structure, and describe how each characteri

stics is related to the molecular structure of water.
Chemistry
1 answer:
makkiz [27]3 years ago
3 0
Water is known as H2O and soil is known as HYG
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Identify each of the following compounds as binary or ternary. Then write the chemical formula for each ionic compound.
Maurinko [17]
Binary compounds have 2 different elements, and ternary compounds have 3
Nickel(III)oxide:  binary, Ni2O3
Copper (II)iodide: binary, CuI2
Tin(IV) nitride: binary, Sn3N4
Chromium (II)bromide: binary, CrBr2
<span>Iron(III)phosphide: binary, FeP</span>
7 0
3 years ago
You observe 2 waves named alpha and beta. The alpha wave has a frequency of 5 Hz and the beta wave has a frequency of 2 Hz. Base
MAVERICK [17]

Answer:

shorter wavelength = alpha wave

Explanation:

Given that,

The alpha wave has a frequency of 5 Hz and the beta wave has a frequency of 2 Hz.

We need to compare the wavelengths of these two waves.

For alpha wave,

\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{5}\\\\=6\times 10^7\ m

For beta wave,

\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{2}\\\\=15\times 10^7\ m

From the above calculations, we find that the wavelength of the alpha wave is shorter than the wavelength of the beta wave.

8 0
3 years ago
The structure of a water molecule (H20) can be written as H-O-H, with each dash representing a chemical bond.
svet-max [94.6K]

Answer:

oxygen shows 2 bonds with hydrogen

8 0
3 years ago
The decomposition of HBr(g) into elemental species is found to have a rate constant of 4.2 ×10−3atm s−1. If 2.00 atm of HBr are
Dennis_Churaev [7]

Answer:

7,94 minutes

Explanation:

If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the r<em>eaction rate does not depend on the concentration of the reactants. </em>

For the zero-order reactions, concentration-time equation can be written as follows:

                                          [A] = - Kt + [Ao]

where:

  • [A]: concentration of the reactant A at the <em>t </em>time,
  • [A]o: initial concentration of the reactant A,
  • K: rate constant,
  • t: elapsed time of the reaction

<u>To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.</u>

Data:

K = 4.2 ×10−3atm/s,  

[A]o=[HBr]o= 2 atm,  

[A]=[HBr]=0 atm (all HBr(g) is gone)

<em>We clear the incognita :</em>

[A] = - Kt + [Ao]............. Kt =  [Ao] - [A]

                                        t  = ([Ao] - [A])/K

<em>We replace the numerical values:</em>

t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes

So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).

6 0
3 years ago
What are the three kind of rocks that are apart of the rock cycle???
pav-90 [236]
Why, Hello There! The 3 Kinds of rocks that are apart of the rock cycle is...

1.S<span>edimentary

2.M</span><span>etamorphic

And
</span><span>
 3.Igneous

Hoped i helped!



</span>
5 0
3 years ago
Read 2 more answers
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