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3 years ago

Food is the only limiting factor that keeps populations from growing too large true or false?

Chemistry

2 answers:

topjm [15]3 years ago

6 0

FALSE

There are other limiting factors like lack of space, diseases, and com petition.

OlgaM077 [116]3 years ago

5 0

The correct answer is False

Explanation:

A limiting factor refers to a condition that stops or limits the growth of a population of any species. Some of these factors include the availability of sources such as food, shelter or water; predation; natural weather conditions; natural disasters; and competence.

The previous idea implies food is not the only factor or condition that would stop or limit the growth of a population but there are many other factors that could prevent a population from growing too large, this includes abiotic factors (nonliving condition) such as weather and biotic factors (living condition) such as competition with other species or individuals or predation.

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The diameter of a biscuit is approximately 51 millimeters (mm). An atom of bismuth (Bi) is approximately 320. picometers (pm) in

astraxan [27]

Answer:

1.5e+8 atoms of Bismuth.

Explanation:

We need to calculate the <em>ratio</em> of the diameter of a biscuit respect to the diameter of the atom of bismuth (Bi):

$\\ \frac{diameter\;biscuit}{diameter\;atom(Bi)}$

For this, it is necessary to know the values in meters for any of these diameters:

$\\ 1m = 10^{3}mm = 1e+3mm$

$\\ 1m = 10^{12}pm = 1e+12pm$

Having all this information, we can proceed to calculate the diameters for the biscuit and the atom in meters.

<h3>Diameter of an atom of Bismuth(Bi) in meters</h3>

1 atom of Bismuth = 320pm in diameter.

$\\ 320pm*\frac{1m}{10^{12}pm} = 3.20*10^{-10}m$

<h3>Diameter of a biscuit in meters</h3>

$\\ 51mm*\frac{1}{10^{3}mm} = 51*10^{-3}m = 5.1*10^{-2}m$

<h3>Resulting Ratio</h3>

How many times is the diameter of an atom of Bismuth contained in the diameter of the biscuit? The answer is the ratio described above, that is, the ratio of the diameter of the biscuit respect to the diameter of the atom of Bismuth:

$\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1*10^{-2}m}{3.20*10^{-10}m}$

$\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1}{3.20}\frac{10^{-2}}{10^{-10}}\frac{m}{m}$

$\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{-2+10}$

$\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{8}=1.5e+8$

In other words, there are 1.5e+8 diameters of atoms of Bismuth in the diameter of the biscuit in question or simply, it is needed to put 1.5e+8 atoms of Bismuth to span the diameter of a biscuit in a line.

6 0

3 years ago

Names of nitrogenousbonucleic bases in dna

Crazy boy [7]

Explanation:

The four nitrogenous bases present in DNA are adenine (A), guanine (G), cytosine (C) and thymine (T).

5 0

3 years ago

Given the balanced equation:

Aliun [14]

Answer:

0.4

Explanation:

Given data:

Number of moles of SrCl₂ consumed = ?

Mass of ZnCl₂ produced = 54 g

Solution:

Chemical equation:

ZnSO₄ + SrCl₂ → SrSO₄ + ZnCl₂

Number of moles of ZnCl₂:

Number of moles = mass/ molar mass

Number of moles = 54 g/136.3 g/mol

Number of moles = 0.4 mol

Now we will compare the moles of ZnCl₂ with SrCl₂ from balance chemical equation.

ZnCl₂ : SrCl₂

1 : 1

0.4 : 0.4

Thus when 54 g of ZnCl₂ produced 0.4 moles of SrCl₂ react.

6 0

3 years ago

fig. 15 shows a simplified diagram of the electrolysis of a molten electrolyte containing lithium chloride. b. Describe how the

melisa1 [442]

During the electrolysis of the molten lithium chloride, the Lithium ions (Li⁺) at the cathode undergoes reduction, and the electron configuration of lithium becomes 1s²2s¹.

<h3>What is electrolysis?</h3>

Electrolysis can be described as the process in which the electric current is passed through the chemical compound to break them. In this process, the atoms and ions are interchanged by the addition or removal of electrons.

The ions are allowed to move freely in this process. When an ionic compound is melted or dissolved in water then ions are produced which can move freely.

During the electrolysis of molten lithium chloride, the lithium ions reach the cathode and accept the electrons while chloride ions reach at anode and loss electrons to become chlorine gas.

At anode : 2 Cl⁻ → Cl₂ + 2e⁻

At cathode: 2 Li⁺ + 2e⁻ → Li

Learn more about electrolysis, here:

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8 0

1 year ago

Do the gas laws apply to liquids ?

Contact [7]

Answer:

The Ideal Gas Law cannot be applied to liquids. The Ideal Gas Law is #PV = nRT#. That implies that #V# is a variable. But we know that a liquid has a constant volume, so the Ideal <u><em>Gas Law cannot apply to a liquid.</em></u>

Explanation:

this is my awnser soory if it was a multiple choice question plz mark brainliest

6 0

3 years ago

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