Explanation:
It is given that,
Relativistic Mass of the stone, m₀ = 0.6
Mass, 
Relativistic mass is given by :
.........(1)
Where
c is the speed of light
On rearranging equation (1) we get :
v = 0.61378 c
or
v = 0.6138 c
So, the correct option is (c). Hence, this is the required solution.
Well, I think it kinda depends on how long the "extended period" is.
If the extended period is a week, a month, or a few months,
then I'd call it a 'cold wave'.
If the extended period is like 100 years or more, then you're
starting to talk 'ice age'.
I think the correct answer from the choices listed above is option C. Lithospheric plates move constantly due to the density differences. Lithospheric plates<span> are another name for tectonic plates, which are part of the Earth's uppermost layer, the crust.</span>
Answer:
i can see it and it looks really cool
Explanation:
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Below is the solution:
<span>T2cos(30) - T1cos(50) = 0
</span><span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span><span>T2cos(30) - T1cos(50) = 0 --> T1 = T2cos(30)/cos(50)
</span>
<span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span>(<span>T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> Solve for T2
</span><span>T1 = -T1cos(50)i + T1sin(50)j
T2 = T2cos(30)i + T2sin(3)j
</span>
<span>(T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 -->
T2[(cos(30)/cos(50))sin(50) + sin(30)] = 75*(grav) -->
T2 = 75*grav/ [(cos(30)/cos(50))sin(50) + sin(30)]
</span>
<span> T2 = 1566.49 </span>
