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DerKrebs [107]
3 years ago
12

A space shuttle with a mass of approximately 7.08 E5 kg is sitting on the launch pad. What would be the weight of the space shut

tle as it prepares for launch?
If there’s any chance work can be shown that would be great, the equation we were told to work with is Wo=mog
Physics
1 answer:
Afina-wow [57]3 years ago
6 0

The weight of the shuttle is 6.94\cdot 10^6 N

Explanation:

The weight of an object on Earth is the gravitational force exerted by the Earth on the object.

The magnitude of the weight of an object is given by:

W=mg

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity on Earth's surface

And the direction is downward (towards the Earth's centre).

For the shuttle in this problem, its mass is

m=7.08\cdot 10^5 kg

So, its weight is

W=(7.08\cdot 10^5)(9.8)=6.94\cdot 10^6 N

Note that while the mass of an object (m) does not change, its weight (W) changes according to the location, since the value of g can be different at different location (for example, on the Moon, the value of g is about 1/6 the value of g on the Earth).

Learn more about weight and forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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The absolute temperature of a gas is t. in order to double the rms speed of its molecules, what should be the new absloute tempe
jenyasd209 [6]

The new absloute temperature should be 4t.

<h3>Temperature </h3>

The hotness of matter or radiation is expressed by the physical quantity known as temperature.

There are three different types of temperature scales: those, like the SI scale, that are defined in terms of the average translational kinetic energy per freely moving microscopic particle, like an atom, molecule, or electron in a body; those that solely depend on strictly macroscopic properties and thermodynamic principles, like Kelvin's original definition; and those that are not defined by theoretical principles but rather by useful empirical properties of particula.

Using a thermometer, one can gauge temperature. It is calibrated using different temperature scales, each of which historically defined itself using a different set of reference points and thermometric materials.

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6 0
2 years ago
A simple pendulum on the surface of Earth is found to undergo 15.0 complete small‑amplitude oscillations in 8.75 s. Find the pen
FinnZ [79.3K]

Answer:

Length of the Pendulum is 14.4 cm

Explanation:

Time period of simple pendulum is given by

T=2\pi \sqrt{\frac{L}{g} } \\

time taken for one oscillation is

T=\frac{time taken}{oscillations} \\T=\frac{8.75}{15} \\T=0.583 s

Pendulum length on the earth surface is

L=\frac{T^2g}{4\pi^2 }\\L=\frac{0.583\times 9.8}{4\pi^2 } \\L=0.144 m

Length of the Pendulum is 14.4 cm

6 0
4 years ago
The compass uses a pendulous system to improve?
ivanzaharov [21]

The compass is designed and developed to use a pendulous system to improve horizontality.

<h3>What is a compass?</h3>

A compass can be defined as a scientific instrument that contains a magnetized pointer, which is used to show and indicate the following four (4) main cardinal directions:

  • North (N)
  • South (S)
  • West (W)
  • East (E)

Basically, the compass is a scientific instrument that's designed and developed to use a pendulous system to improve horizontality.

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6 0
2 years ago
Consider an unknown charge that is released from rest at a particular location in an electric field so that it has some initial
sineoko [7]

Answer:

b)

Explanation:

If the charge is released at rest in an electric field, it will move along the electric field, going to regions of higher electric potential if it is a negative charge (against the field direction) and towards lower potential regions if it is positive (along the field). This means that the charge will gain kinetic energy, energy that only can come from a decrease in the electric potential energy.

For a positive charge: ΔEp = q*ΔV < 0 (as ΔV < 0)

For a negative charge: ΔEp = (-q) *ΔV < 0 (as ΔV > 0)

4 0
3 years ago
An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is
vichka [17]
Using F = Ke
F = 39200×(25÷100) = 39200×0.25
F= 9800N
8 0
4 years ago
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