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DerKrebs [107]
3 years ago
12

A space shuttle with a mass of approximately 7.08 E5 kg is sitting on the launch pad. What would be the weight of the space shut

tle as it prepares for launch?
If there’s any chance work can be shown that would be great, the equation we were told to work with is Wo=mog
Physics
1 answer:
Afina-wow [57]3 years ago
6 0

The weight of the shuttle is 6.94\cdot 10^6 N

Explanation:

The weight of an object on Earth is the gravitational force exerted by the Earth on the object.

The magnitude of the weight of an object is given by:

W=mg

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity on Earth's surface

And the direction is downward (towards the Earth's centre).

For the shuttle in this problem, its mass is

m=7.08\cdot 10^5 kg

So, its weight is

W=(7.08\cdot 10^5)(9.8)=6.94\cdot 10^6 N

Note that while the mass of an object (m) does not change, its weight (W) changes according to the location, since the value of g can be different at different location (for example, on the Moon, the value of g is about 1/6 the value of g on the Earth).

Learn more about weight and forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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Answer:

a)η = 69.18 %

b)W= 1210 J

c)P=3967.21 W

Explanation:

Given that

Q₁ = 1749 J

Q₂ = 539  J

From first law of thermodynamics

Q₁   = Q₂ +W

W=Work out put

Q₂=Heat rejected to the cold reservoir

Q₁ =heat absorb by hot  reservoir

W= Q₁- Q₂

W= 1210 J

The efficiency given as

\eta=\dfrac{W}{Q_1}

\eta=\dfrac{1210}{1749}

\eta=0.6918

η = 69.18 %

We know that rate of work done is known as power

P=\dfrac{W}{t}

P=\dfrac{1210}{0.305}\ W

P=3967.21 W

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