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DerKrebs [107]
2 years ago
12

A space shuttle with a mass of approximately 7.08 E5 kg is sitting on the launch pad. What would be the weight of the space shut

tle as it prepares for launch?
If there’s any chance work can be shown that would be great, the equation we were told to work with is Wo=mog
Physics
1 answer:
Afina-wow [57]2 years ago
6 0

The weight of the shuttle is 6.94\cdot 10^6 N

Explanation:

The weight of an object on Earth is the gravitational force exerted by the Earth on the object.

The magnitude of the weight of an object is given by:

W=mg

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity on Earth's surface

And the direction is downward (towards the Earth's centre).

For the shuttle in this problem, its mass is

m=7.08\cdot 10^5 kg

So, its weight is

W=(7.08\cdot 10^5)(9.8)=6.94\cdot 10^6 N

Note that while the mass of an object (m) does not change, its weight (W) changes according to the location, since the value of g can be different at different location (for example, on the Moon, the value of g is about 1/6 the value of g on the Earth).

Learn more about weight and forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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Three things that effect a life system would be
- sunlight
-water
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2 years ago
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You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
stellarik [79]

A) The change in internal chemical energy is 1.15\cdot 10^7 J

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

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3 0
2 years ago
The force of an electric field is proportional to to electric charge? True or False
tamaranim1 [39]

Answer:True

Explanation:

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What automotive system keeps the vehicle's tires in contact with the road?        A. The steering system   B. The suspension sys
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The answer is D transmission
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The speed of the incoming water is 25 cm/s and the cross-sectional area of the hose carrying the water is 2.0 cm2. 1) Determine
Sindrei [870]

Answer:

The time taken is  t = 500 \ s

Explanation:

From the question are told that

  The speed of the incoming water is  v =  25 cm/s

  The cross-sectional area of the host pipe is  a = 2.0 cm^2

Generally the rate at which the container is been filled is mathematically represented as

         \r  V  =  v *  a

=>      \r  V  = 25 * 2

=>      \r  V  = 50\  cm^3/s

Generally 2.5  L  =  25000 cm^3

Generally the time taken is  mathematically represented as

      t = \frac{25000}{50}

=>   t = 500 \ s

6 0
2 years ago
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