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3 years ago

A net force of 100 N is moving a mass with an acceleration of 5 m/s2. What is the mass of the object?

Physics

1 answer:

olya-2409 [2.1K]3 years ago

7 0

Fnet=ma so m = fnet/a 100/5=20 the mass is 20

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The 16.0-in. spring is compressed to a 9.9-in. length, where it is released from rest and accelerates the sliding block A. The a

Jlenok [28]

Answer:

Part a : Time required for the block to go to 3.05 in is 0.036 s

Part b : Time required for the block to go to 6.1 in is 0.054 s

Explanation:

The acceleration is given as

$a=a_o-kx$

Here

$a_o$ is the initial acceleration which is given as 420 $ft/s^2$
k is the spring constant which is calculated as follows

$k=\frac{a_o}{l_c-l_{uc}}$

Here lc is the compressed length of the spring
and Iuc is the uncompressed length of the spring so the value of k is

$k=\frac{420}{\frac{16-9.9}{12}}\\k=826.22 s^{-2}$

So now the equation becomes

$a=420-826.23x$

As per relation of acceleration to velocity

$vdv=adx$

$\int\limits^v_0 {v} \, dv =\int a dx$

$\frac{v^2}{2} =\int (420-826x) dx$

$\frac{v^2}{2} =420x-413x^2$

${v^2}=840x-826x^2\\{v}=\sqrt{840x-826x^2}\\$

Also

$v=\frac{dx}{dt}$

$\frac{dx}{dt}=\sqrt{840x-826x^2}\\$

Solving for dt and integrating results in

${dt}=\frac{dx}{\sqrt{840x-826x^2}}\\\int\limits^t_0 \,dt=\int\limits^x_0 \,\frac{dx}{\sqrt{840x-826x^2}}\\t=\int\limits^x_0 \,\frac{dx}{\sqrt{840x-826x^2}}$

Now using this equation value for both parts can be calculated numerically as

Part a 3.05 in

$x=\frac{3.05}{12}\\x=0.254 ft$

Solving numerically for this value of x

$t=\int\limits^{0.254}_0 \,\frac{dx}{\sqrt{840x-826x^2}}\\t=0.036 s$

Time required for the block to go to 3.05 in is 0.036 s

Part b 6.1 in

$x=\frac{6.1}{12}\\x=0.504 ft$

Solving for this value of x

$t=\int\limits^{0.504}_0 \,\frac{dx}{\sqrt{840x-826x^2}}\\t=0.0543 s$

Time required for the block to go to 6.1 in is 0.054 s

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3 years ago

A truck is traveling with 50,000 J of kinetic energy. It

Ket [755]

Answer: It hits the brakes and the truck now has only 20000J of kinetic energy

Explanation:

Hope it help you

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3 years ago

Ac=v^2/r solve for v, solve for r

bazaltina [42]

Answer:

v = √ac×r

r = $\frac{v^2}{ac}$

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3 years ago

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Einstein and lorentz, being avid tennis players, play a fast-paced game on a court where they stand 19.0 m from each other. bein

Dvinal [7]

So sometimes when you actually do you work it’s happens and you get answers idk about that

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3 years ago

Electromagnetic waves can behave like particles

Ilya [14]

Yes they can. Uh-huh. Indubitably. That's right, Vanessa. It's true.

A better way to say it might be:

Electromagnetic radiation can behave like waves AND like particles.

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3 years ago