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inessss [21]
2 years ago
10

A compound that would be most soluble in water would be: a. glucose b. cholesterol. c. a large protein. d. a triglyceride.

Chemistry
1 answer:
Mrrafil [7]2 years ago
5 0

Answer:

a. glucose

Explanation:

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Conversation 13kg into gram<br>4 poi ts<br>​
Olenka [21]

Answer:

13000

Explanation:

The kilogram, or kilogramme, is the base unit of weight in the Metric system. It is the approximate weight of a cube of water 10 centimeters on a side.

A gram is a unit of weight equal to 1/1000th of a kilogram. A gram is the approximate weight of a cubic centimeter of water.

5 0
3 years ago
A student developed a chromatogram and found that the cluent front traveled 94 mm and the Zn²+ cation traveled
Valentin [98]

Answer:

srry i can't answer that

Explanation:

4 0
1 year ago
If 700 g of water at 90 °C loses 27 kJ of heat, what is its final temperature?​
Phoenix [80]

Answer:

If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also increases; and the same happens when either of the two decreases .). The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature, ΔT= Tfinal - Tinitial

In this case:

  • Q= 27 kJ= 27,000 J (being 1 kJ=1,000 J)
  • c=4.186 \frac{J}{g* C}
  • m=700 g
  • ΔT= Tfinal - Tinitial= Tfinal - 90 °C

Replacing:

27,000 J=4.186 \frac{J}{g* C}*400 g* (Tfinal - 90C)\\

Solving:

27,000 J=1,674.4 \frac{J}{C}* (Tfinal - 90C)

\frac{27,000 J}{1,674.4 \frac{J}{C}} =(Tfinal - 90C)

16.125 °C= Tfinal - 90 °C

Tfinal= 16.125 °C + 90 °C

Tfinal= 106.125 °C

<u><em>If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C</em></u>

3 0
3 years ago
Unabbreviated electron configuration of magnesium
fenix001 [56]

Answer:

Mg₁₂ = 1s² 2s² 2p⁶ 3s²

Explanation:

Abbreviated and unabbreviated electronic configuration:

The abbreviated electronic configuration uses the noble gas configuration i.e complete electronic shells. For example, the atomic number of neon is ten and magnesium is twelve. The abbreviated electronic configuration of magnesium is written by using the neon abbreviation in following way:

The electronic configuration of neon is given below:

Ne₁₀ = 1s² 2s² 2p⁶

The abbreviated electronic configuration of magnesium:

Mg₁₂ = [Ne] 3s²

While the unabbreviated electronic configuration is written without using noble gas electronic configuration.

Unabbreviated electronic configuration of magnesium:

Mg₁₂ = 1s² 2s² 2p⁶ 3s²

5 0
3 years ago
Briefly explain whether the following procedural errors would result in either an incorrectly high or incorrectly low calculated
seropon [69]
<span>A) This solution was not basic when it was heated in part 3. ( in part 3 i convertedCu(OH)2 to CuO).
Incorrectly low, because not all copper compounds will precipitate out

B) A slightly blue solution was decanted from Cu in part V. (in part 5 i reduced Cu(H20)6 ions with zink)
Incorrectly low, because some copper were thrown away

C) In part 5 the water in the beaker boiled away, exposing the evaporating dish to excess heat (same as above).
incorrectly high, because other compounds might be present as well </span>
7 0
2 years ago
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