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Leno4ka [110]
2 years ago
12

Zn2+ and Al3+ are amphoteric. Demonstrate

Chemistry
1 answer:
denis23 [38]2 years ago
8 0

Explanation:

1) Amphoteric substances can react both like an acid or a base depending if they are in presence of a base or an acid.

Zinc hydroxide (Zn(OH)2):

In acid: Zn(OH)_2 + 2 HCl \longrightarrow ZnCl_2 + 2 H_2O


In base: Zn(OH)_2 + 2 NaOH \longrightarrow Na_2[Zn(OH)_4]

Aluminium hydroxide (Al(OH)3)

In acid: Al(OH)_3 + 3 HCl \longrightarrow AlCl_3 + 3 H_2O


In base: Al(OH)_3 + NaOH \longrightarrow Na[Al(OH)_4]

2) Reactions

a) 2 NH_3 + Cu^{2+} + 2 H_2O \longrightarrow 2 NH_4^+ + Cu(OH)_2

3 NH_3 + Fe^{3+} + 3 H_2O \longrightarrow 3 NH_4^+ + Fe(OH)_3

b) 2 NH_3 + Zn^{2+} + 2 H_2O \longrightarrow 2 NH_4^+ + Zn(OH)_2

3 NH_3 + Al^{3+} + 3 H_2O \longrightarrow 3 NH_4^+ + Al(OH)_3

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The combined mass of all the protons and electrons is 24.305.

Explanation:

From the information given about the atom, we can see that the relative atom mass of the element is 24.305.

The relative atomic mass of an atom is the combined mass of all its isotope in proportion of their geonormal abundances. On the periodic table, this mass deals with the amount of protons and neutrons present in a given atom.

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How the relative density of a substance is related to the density calculate the density of iron if its relative density is 2 and
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How the relative density of a substance is related to the density calculate the density of iron if its relative density is 2 and a density of water is 2gcm -3

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Question about thermodynamics
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For the following reaction, 6.94 grams of water are mixed with excess sulfur dioxide . Assume that the percent yield of sulfurou
Alexxx [7]
<h3>Answer:</h3>

#a. Theoretical yield = 31.6 g

#b. Actual yield = 25.72 g

<h3>Explanation:</h3>

The equation for the reaction between sulfur dioxide and water to form sulfurous acid is given by the equation;

SO₂(g) + H₂O(l) → H₂SO₃(aq)

The percent yield of H₂SO₃ is 81.4%

Mass of water that reacted is 6.94 g

#a. To get the theoretical yield of H₂SO₃ we need to follow the following steps

Step 1: Calculate the moles of water

Molar mass of water = 18.02 g/mol

Mass of water = 6.94 g

But, moles = Mass/molar mass

Moles of water = 6.94 g ÷ 18.02 g/mol

                        = 0.385 mol

Step 2: Calculate moles of H₂SO₃

From the equation, the mole ratio of water to H₂SO₃ is 1 : 1

Therefore, moles of water = moles of H₂SO₃

Hence, moles of H₂SO₃ = 0.385 mol

Step 3: Theoretical mass of H₂SO₃

Mass = moles × Molar mass

Molar mass of H₂SO₃ = 82.08 g/mol

Number of moles of H₂SO₃ = 0.385 mol

Therefore;

Theoretical mass of H₂SO₃ = 0.385 mol ×  82.08 g/mol

                                             = 31.60 g

Thus, the theoretical yield of H₂SO₃ is 31.6 g

<h3>#b. Calculating the actual yield</h3>

We need to calculate the actual yield

Percent yield of H₂SO₃ is 81.4%

Theoretical yield is 31.60 g

But; Percent yield = (Actual yield/theoretical yield)×100

Therefore;

Actual yield = Percent yield × theoretical yield)÷ 100

                   = (81.4 % × 31.6) ÷ 100

                  = 25.72 g

The percent yield of H₂SO₃ is 25.72 g

6 0
3 years ago
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