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3 years ago

Which material is not a conductor of electrical current?

Engineering

1 answer:

olya-2409 [2.1K]3 years ago

7 0

Answer:

plastic

Explanation:

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A liquid jet vj of diameter dj strikes a fixed cone and deflects back as a conical sheet at the same velocity. find the cone ang

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lol i cant real it sorry

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2 years ago

Determine if the following errors are systematic or random. Justify your response. (a) Effect of temperature on the circuitry of

k0ka [10]

Answer:

a) temperature: random error

b) parallax: systematic error

c) using incorrect value: systematic error

Explanation:

Systematic errors are associated with faulty calibration or reading of the equipments used and they could be avoided refining your method.

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3 years ago

After a strong storm, a worker does not realize that a power transmission line has fallen on his car and is electrocuted while o

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Answer and Explanation:

The correct answer choice is Contacting Overhead Power Lines.

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2 years ago

At steady state, a reversible refrigeration cycle discharges energy at the rate QH to a hot reservoir at temperature TH, while r

ludmilkaskok [199]

Answer:

a) $COP_{R} = 25.014$ , b) $T_{H} = 327.78\,K\,(54.63\,^{\textdegree}C)$

Explanation:

a) The coefficient of performance of a reversible refrigeration cycle is:

$COP_{R} = \frac{T_{L}}{T_{H}-T_{L}}$

Temperatures must be written on absolute scales (Kelvin for SI units, Rankine for Imperial units)

$COP_{R} = \frac{275.15\,K}{286.15\,K-275.15\,K}$

$COP_{R} = 25.014$

b) The respective coefficient of performance is determined:

$COP_{R} = \frac{Q_{L}}{Q_{H}-Q_{L}}$

$COP_{R} = \frac{8.75\,kW}{10.5\,kW-8.75\,kW}$

$COP_{R} = 5$

But:

$COP_{R} = \frac{T_{L}}{T_{H}-T_{L}}$

The temperature at hot reservoir is found with some algebraic help:

$COP_{R} \cdot (T_{H}-T_{L})=T_{L}$

$T_{H}-T_{L} = \frac{T_{L}}{COP_{R}}$

$T_{H} = T_{L}\cdot \left(1+\frac{1}{COP_{R}} \right)$

$T_{H} = 273.15\,K \cdot \left(1+\frac{1}{5} \right)$

$T_{H} = 327.78\,K\,(54.63\,^{\textdegree}C)$

8 0

3 years ago

Read 2 more answers

During Atterberg limit tests in the soil mechanics laboratory, the students obtained the following results from a clayey soil. L

m_a_m_a [10]

the liquid limit

LL=-0.8078x*49.503

LL=-0.8078(25)+49.503

LL=29.308

plasticity index of the soil

PL=217.2%+17.8%/2

PL=17.5

PI=LL-PL

PI=29.308-17.5

PL=11.808

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)

- Cutiepatutie ☺❀❤

6 0

3 years ago