Question

A jetliner, traveling northward, is landing with a speed of 71.9 m/s. Once the jet touches down, it has 675 m of runway in which to reduce its speed to 11.3 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing (take the direction of the plane's motion as positive).

Answer 1

Answer:

The value is  $a = -3.7 \ m/s^2$

Explanation:

From the question we are told that

   The  landing speed is  $u = 71.9 \ m/s$

   The  distance traveled is  $d = 675 \ m$

    The velocity it is reduced to is  $v = 11.3 \ m/s$

   

Generally the average acceleration is mathematically represented as

      $a = \frac{ v^2 - u^2 }{ 2 * d }$

=>  $a = \frac{ 11.3^2 - 71.9^2 }{ 2 * 675 }$

=>   $a = -3.7 \ m/s^2$