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STatiana [176]
3 years ago
8

Describe the relationship between a compass and a magnet. Use C.E.R while answering. Your CER should have a one-sentence claim,

three evidence pieces, and two reasoning sentences that explain why you chose your evidence.
Physics
2 answers:
Allushta [10]3 years ago
6 0

Answer:

Magnets interfere with compasses because compasses use the magnetic field to locate NESW (north east south west)

Explanation:

xxTIMURxx [149]3 years ago
4 0
C - Yes there is a relationship between a compass and magnet.

E
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can someone change the words in this (the change in position of one object compared to the position of another ​
adell [148]

change of an object relative to the position of another object.

3 0
4 years ago
A pool can be filled by a pipe in 3 hours. it takes 3 times as long for another pipe to empty the pool. how long will it take to
Mila [183]

There is need 4.5 hours to fill the pool in case if both pipes are open

7 0
3 years ago
4. A 70.0 kg boy and a 45.0 kg girl use an elastic rope while engaged in a tug-of-war on an icy,
marta [7]

Answer:

a_1 = 1.446m/s^2

Explanation:

Given

m_1 = 70.0kg -- Mass of the boy

m_2 = 45.0kg -- Mass of the girl

a_2 = 2.25m/s^2 -- Acceleration of the girl towards the boy

Required

Determine the acceleration of the boy towards the girl (a_1)

From the question, we understand that the surface is frictionless. This implies that the system is internal and the relationship between the given and required parameters is:

m_1 * a_1 = m_2 * a_2

Substitute values for m_1, m_2 and a_2

70.0 * a_1 = 45.0 * 2.25

Make a_1 the subject

\frac{70.0 * a_1}{70.0} = \frac{45.0 * 2.25}{70.0}

a_1 = \frac{45.0 * 2.25}{70.0}

a_1 = \frac{101.25}{70.0}

a_1 = 1.446m/s^2

<em>Hence, the acceleration of the boy towards the girl is 1.446m/s^2</em>

7 0
3 years ago
Learning Goal: To practice Problem-Solving Strategy 7.1 Rotational dynamics problems. Suppose that you are holding a pencil bala
aliya0001 [1]

Answer:

when the pencil is balanced on a point it is motionless due to net force only acting trough the center, but when we release the position we are changing the location of a pencil hence due to turning affect it will expericence torque and the angular acceleration produced.

for the complete answer the length and mass of pencil should be known i am giving the general expression for the calculation of angular acceleration

Explanation:

<h3>τ=Iα</h3><h3>τ= torque</h3><h3>I = inertia</h3><h3>α= angular acceleration</h3>

where

I= mL^2/3 (by geometry of pencil)

when the pencil is released it will experience force due to weight

F=mgsinθ

so τ=Fxd

τ=mgsin(10°)x(L/2)

then.

α=τ/I

α=mgsin(10°)xL/2÷(mL^2)/3

6 0
3 years ago
A light, rigid rod is 55.8 cm long. Its top end is pivoted on a frictionless horizontal axle. The rod hangs straight down at res
VMariaS [17]

To solve this problem we will apply the principle of conservation of energy. For this purpose, potential energy is equivalent to kinetic energy, and this clearly depends on the position of the body. In turn, we also note that the height traveled is twice that of the rigid rod, therefore applying these concepts we will have

KE = PE

\frac{1}{2} mv^2 = mgh

v = \sqrt{2gh}

v = \sqrt{2(9.8)(2(55.8*10^{-2}))}

v = 4.67m/s

Therefore the minimum speed at the bottom is required to make the ball go over the top of the circle is 4.67m/s

4 0
3 years ago
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