1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksandr82 [10.1K]
3 years ago
10

Which contains more molecules; 1mol H2O2, 1mol C2H6, or 1mol CO?

Chemistry
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer:

C2H6

Explanation:

You might be interested in
A student does not observe a change when holding a test tube in a flame. However, a change is expected. What is the most likely
dalvyx [7]

The answer is: The reactants were not heated long enough.

For all chemical reaction some energy is required and that energy is called activation energy (energy that needs to be absorbed for a chemical reaction to start).

Activation energy is the minimum energy colliding particles must have in order to react.

By lowering activation energy, reaction need less heat.

In this example, there is not enough heat.

3 0
3 years ago
Read 2 more answers
How many moles of o2 are required for the complete reaction of 54.7 g of c2h4 to form co2 and h2o?
Hunter-Best [27]
The balanced chemical equation that illustrates this reaction is:
<span>C2H4 + 3O2 --> 2CO2 + 2H2O 
</span>
From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
Therefore:
molar mass of C2H4 = 12(2) + 4(1) = 24 + 4 = 28 grams

number of moles = mass / molar mass
number of moles of C2H4 = 54.7 / 28 = 1.95 moles

From the balanced equation above:
3 moles of oxygen are required to react with one mole of C2H4, therefore, to know the number of moles required to react with 1.95 moles of C2H4, all you have to do is cross multiplication as follows:
number of oxygen moles = (1.95*3) / 1 = 5.85 moles
4 0
3 years ago
Read 2 more answers
Concentration in ppm containing 30 grams NaNO3 in 70 grams H2O
Reika [66]
110 g at 40°C

See explanation
5 0
3 years ago
The amount of calcium hydroxide needed to react completely with 100.0g of nitric acid
Pani-rosa [81]

The amount of Calcium hydroxide : = 58.719 g

<h3>Further explanation</h3>

Given

100 g Nitric Acid-HNO₃

Required

The amount of Calcium hydroxide

Solution

Reaction(balanced) :

Ca(OH)₂ (s) + 2HNO₃ (aq) → Ca(NO₃)₂ (aq) + 2H₂O (l)

mol of Nitric acid (MW 63 g/mol) :

mol = mass : MW

mol = 100 : 63

mol = 1.587

From the equation, mol ratio of Ca(OH)₂ : HNO₃ = 1 : 2, so mol Ca(OH)₂ :

=1/2 x mol HNO₃

= 1/2 x 1.587

=0.7935

Mass of Ca(OH)₂ (MW=74 g/mol) :

= mol x MW

= 0.7935 x 74

= 58.719 g

5 0
3 years ago
Conclusion
Natalija [7]

whats the question?

8 0
3 years ago
Other questions:
  • Help lol
    15·2 answers
  • What is the ph of a buffer consisting of 0.200 m hc2h3o2 and 0.200 m kc2h3o2? the k a for hc2h3o2 is 1.8×10−5. view available hi
    7·1 answer
  • In an experiment, dilute hydrochloric acid reacts with a white solid and bubbles of gas are produced. If this gas is bubbled thr
    12·1 answer
  • A sample of radium-226 contains 1.0×108 atoms of radium-226. How many atoms of radium-226 will remain in the sample after three
    5·1 answer
  • Problem PageQuestion A chemistry student weighs out of acetic acid into a volumetric flask and dilutes to the mark with distille
    10·1 answer
  • Luca wants to identify and quantity the chemicals causing air pollution in a city, but he is using a manual air sampler to colle
    15·1 answer
  • Which metal is more reactive calcium or cobalt
    12·1 answer
  • Part a how many carbon atoms are in a 2-carat pure diamond that has a mass of 0.40 g . express your answer using two significant
    9·1 answer
  • What is the "magic number' of valence electrons? How does this influence the type of bonds formed by various combinations of
    14·1 answer
  • Name two elements in the modern periodic table that break Mendeléey's rule that the elements should be arranged in order of rela
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!