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Aleksandr-060686 [28]
3 years ago
9

What is the oxidation number of Cl in chlorate ion ClO3?

Chemistry
2 answers:
Kryger [21]3 years ago
8 0

The correct answer to this question is "5." the oxidation number of cl in ClO3 will be a positive 5 because oxygen is naturally a -2 charge. times that by three and then account for the negative charge of the CLO3- ion.

Varvara68 [4.7K]3 years ago
5 0

Answer is: the oxidation number of Cl (chlorine) in chlorate ion is +5.

Chlorate ion (ClO₃⁻) has negative charge.

One oxygen atom in this anion (negatively charged ion) has the oxidation number -2. There are three oxygen atoms in chlorate anion.

x + 3 · (-2) = -1.

x = -1 + 6.

x = +5; the oxidation number of chlorine.

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Answer:

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Explanation:

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6 0
3 years ago
1. Calculate the average reaction rate expressed in moles H2 consumed per liter per second.
valentina_108 [34]

Answer:

1) 0.0025 mol/L.s.

2) 0.0025 mol/L.s.

Explanation:

  • For the reaction:

<em>H₂ + Cl₂ → 2HCl.</em>

<em></em>

<em>The average reaction rate = - Δ[H₂]/Δt = - Δ[Cl₂]/Δt = 1/2 Δ[HCl]/Δt</em>

<em></em>

<em>1. Calculate the average reaction rate expressed in moles H₂ consumed per liter per second.</em>

<em></em>

The average reaction rate expressed in moles H₂ consumed per liter per second = - Δ[H₂]/Δt = - (0.02 M - 0.03 M)/(4.0 s) = 0.0025 mol/L.s.

<em>2. Calculate the average reaction rate expressed in moles CI₂ consumed per liter per second.</em>

<em></em>

The average reaction rate expressed in moles Cl₂ consumed per liter per second = - Δ[Cl₂]/Δt = - (0.04 M - 0.05 M)/(4.0 s) = 0.0025 mol/L.s.

7 0
3 years ago
What volume is show in this picture?
Anarel [89]

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8 0
2 years ago
How to do dots and cross diagrams
Likurg_2 [28]

Answer:

Draw circles to represent the electron shell of each atom overlapping the circles where the atoms are bonded. Add dots to represent the outer electrons of one type of atom (H). Add crosses to represent the outer electrons of the other type of atom (Cl). Make sure the electrons are always in pairs.

6 0
2 years ago
The substance water always has a mass ratio of 11% H to 89% O. If 5.00g of a substance containing H and O was decomposed into .2
Gre4nikov [31]

Answer:

                    No the substance is not water.

Explanation:

                   The balance chemical equation for the decomposition of water is as follow;

                                           2 H₂O = 2 H₂ + O₂

Step 1: <u>Calculate moles of H₂O;</u>

               Moles  =  Mass / M.Mass

               Moles  =  5.0 g / 18.01 g/mol

               Moles  =  0.277 moles of H₂O

Step 2: <u>Calculate Moles of O₂ and H₂ produced by 0.277 moles of H₂O:</u>

According to equation,

                        2 moles of H₂O produced  =  1 mole of O₂

So,

                  0.277 moles of H₂O will produce  =  X moles of O₂

Solving for X,

                     X =  0.277 mol × 1 mol / 2 mol

                     X =  0.138 moles of O₂

Also,

According to equation,

                        2 moles of H₂O produced  =  2 mole of H₂

So,

                  0.277 moles of H₂O will produce  =  X moles of H₂

Solving for X,

                     X =  0.277 mol × 2 mol / 2 mol

                     X =  0.227 moles of H₂

Step 3: <u>Calculate Mass of O₂ and H₂ as;</u>

For O₂:

                 Mass  =  Moles × M.Mass

                 Mass  =  0.138 mol × 31.99 g/mol

                 Mass  =  4.44 g of O₂

For H₂:

                 Mass  =  Moles × M.Mass

                 Mass  =  0.227 mol × 2.01 g/mol

                 Mass  =  0.559 g of H₂

Conclusion:

                   From conclusion it is proved that the amount of H₂ produced by decomposition of 5 g of water should be 0.559 g while in statement it is less i.e. 0.290 g.

6 0
3 years ago
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