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galina1969 [7]
3 years ago
6

Jack and Jill went up the hill to fetch a pail of water. Jack, who’s mass is 75 kg, 1.5 times heavier than Jill’s mass, fell

down and broke his crown after climbing a 15 m high hill. Jillcame tumbling after covering the same distance as Jack in 1/3rd of the time.Required:a. Who did the most work climbing up the hill? b. Who applied the most power?
Physics
1 answer:
Travka [436]3 years ago
3 0

Answer:

<em>a) Jack does more work uphill</em>

<em>b) Numerically, we can see that Jill applied the most power downhill</em>

<em></em>

Explanation:

Jack's mass = 75 kg

Jill's mass = 1.5x = 75

Jill's mass = x = \frac{75}{1.5} = 50 kg

distance up hill = 15 m

a) work done by Jack uphill = mgh

where g = acceleration due to gravity= 9.81 m/s^2

work = 75 x 9.81 x 15 = <em>11036.25 J</em>

similarly,

Jill's work uphill = 50 x 9.81 x 15 = <em>7357.5 J</em>

<em>this shows that Jack does more work climbing up the hill</em>

<em></em>

b) assuming Jack's time downhill to be t,

then Jill's time = \frac{t}{3}

we recall that power is the rate in which work id done, i.e

P = \frac{work}{time}

For Jack, power = \frac{11036.25}{t}

For Jill, power =  \frac{3*7357.5}{t} =  \frac{22072.5}{t}

<em>Numerically, we can see that Jill applied the most power downhill</em>

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