Answer:
<em>a) Jack does more work uphill</em>
<em>b) Numerically, we can see that Jill applied the most power downhill</em>
<em></em>
Explanation:
Jack's mass = 75 kg
Jill's mass = 
Jill's mass =
= 50 kg
distance up hill = 15 m
a) work done by Jack uphill = mgh
where g = acceleration due to gravity= 9.81 m/s^2
work = 75 x 9.81 x 15 = <em>11036.25 J</em>
similarly,
Jill's work uphill = 50 x 9.81 x 15 = <em>7357.5 J</em>
<em>this shows that Jack does more work climbing up the hill</em>
<em></em>
b) assuming Jack's time downhill to be t,
then Jill's time = 
we recall that power is the rate in which work id done, i.e
P = 
For Jack, power =
For Jill, power =
=
<em>Numerically, we can see that Jill applied the most power downhill</em>