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DerKrebs [107]
3 years ago
9

Learning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement

Physics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

Woke done, W = 4156.92 Joules

Explanation:

The work done by the force can be calculated as :

W=F\times s

W=Fs\ cos\theta

\theta is the angle between force and the displacement

It is assumed to find the work done for the given parameters i.e.

Force, F = 30 N

Distance travelled, s = 160 m

Angle between force and displacement, \theta=30

Work done is given by :

W=Fs\ cos\theta

W=30\times 160\ cos(30)

W = 4156.92 Joules

So, the work done by the object is 4156.92 Joules. Hence, this is the required solution.

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Earth's subsystems are the geosphere, atmosphere, hydrosphere, and biosphere. Energy and matter are transferred when Earth's sub
Leona [35]

Answer:

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Explanation:

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The Earth system is powered by energy from two major sources: the Sun and the planet's internal heat.

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6 0
3 years ago
Which of the following is an example of an electromagnetic wave?
Gnom [1K]

light from a neon sign


3 0
3 years ago
An organ pipe is made to play a low note at 27.5 Hz, the same as the lowest note on a piano. Assuming a sound speed of 343 m/s,
timama [110]

Answer:

The length of open-open pipe needed is 6.23 m

The length of open-close  pipe needed is 3.11 m

Explanation:

Fundamental frequency for standing wave mode of  an open- open pipe is given by

f=\frac{v}{2L}

where v is the velocity and L is the length

The length of open-open pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

Fundamental frequency for standing wave mode of  an open- close pipe is given by

f=\frac{v}{2L}

The length of open-close pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

7 0
3 years ago
A 0N<br> B 6N<br> C 10 N<br> D 12 N
umka21 [38]

Answer:

<em>The net force acting on the object is 0 N</em>

Explanation:

<u>Newton's Second Law of Forces</u>

The net force acting on a body is proportional to the mass of the object and its acceleration.

The net force can be calculated as the sum of all the force vectors in each rectangular coordinate separately.

The image shows a free body diagram where four forces are acting: two in the vertical direction and two in the horizontal direction.

Note the forces in the vertical direction have the same magnitude and opposite directions, thus the net force is zero in that direction.

Since we are given the acceleration a =0, the net force is also 0, thus the horizontal forces should be in equilibrium.

The applied force of Fapp=10 N is compensated by the friction force whose value is, necessarily Fr=10 N in the opposite direction.

The net force acting on the object is 0 N

3 0
3 years ago
Assume that in interstellar space the distance between two electrons is about 0.8 cm. The electric force between the two electro
SIZIF [17.4K]

Answer:

F = 3.6 x 10⁻²⁴ N

Explanation:

The force of attraction or repulsion between two charges is given by the Coulomb's Law. Coulomb's Law states that:

F = kq₁q₂/r²

where,

F = Electric Force between electrons = ?

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q₁ = q₂ = Charge on electron = 1.6 x 10⁻¹⁹ C

r = distance between electrons = 0.8 cm = 0.008 m

Therefore,

F = (9 x 10⁹ N.m²/C²)(1.6 x 10⁻¹⁹ C)(1.6 x 10⁻¹⁹ C)/(0.008 m)²

<u>F = 3.6 x 10⁻²⁴ N</u>

5 0
3 years ago
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