Answer:
Option B. 4.25×10¯¹⁹ J
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 6.42×10¹⁴ Hz
Energy (E) =?
Energy and frequency are related by the following equation:
Energy (E) = Planck's constant (h) × frequency (f)
E = hf
With the above formula, we can obtain the energy of the photon as follow:
Frequency (f) = 6.42×10¹⁴ Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 6.42×10¹⁴
E = 4.25×10¯¹⁹ J
Thus, the energy of the photon is 4.25×10¯¹⁹ J
Answer:
It indicates that the ratio of the particles in the composition of the sample will always be 2:1 with Hydrogen: Sulfur
3.4 molecules is in 127 grams of iodine
The correct answer would be the first one. The reaction that will not conduct electricity would be CH3OH(l) = CH3OH(aq) since it stays as a single molecule in solution. It does not have any free electrons that will allow the flow of current into the solution. Other options dissociates into ions which has free electrons so they allow current to flow.
