The energy equivalent of 5.0 kg mass would be <span>4.5x10^17.</span>
The coefficient of friction between the sled and the snow is 0.119.
To find the answer, we need to know about the friction.
<h3>How to find the coefficient of friction between the sled and the snow?</h3>
- Whenever a body moves over the surface of another body, a force come into play, which acts parallel to the surface of contact and oppose the relative motion. This opposing force is called friction.
- To solve the problem, we have to draw the free body diagram of the given system.
- We have given with the following values,
Here, acceleration will be equal to zero, because the velocity is given as constant.
- Thus, from the diagram, we can write the balancing equations as follows,
- Substituting N in f and f in the equation of ma, then we get,
- Substituting values, we get the coefficient of friction as,
Thus, we can conclude that, the coefficient of friction between the sled and the snow is 0.119.
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Answer:
Explanation:
Given
See attachment
Required
Determine PCD and CPD
First, we need to calculate CPD
Since DPA is a straight line and CPA = 100;
We have that:
--- angle on a straight theorem
Substitute 100 for CPA
Subtract 100 from both sides
Next, we calculate PCD
We have that:
--alternate angle
In triangle PCD
--- angles in a triangle
Where
So, we have:
Subtract 136 from both sides
Answer:
Amplitude, A = 0.049 meters
Explanation:
Given that,
A harmonic wave travels in the positive x direction at 6 m/s along a taught string. A fixed point on the string oscillates as a function of time according to the equation :
.......(1)
The general equation of a wave is given by :
.......(2)
A is amplitude of wave
On comparing equation (1) and (2) we get :
A = 0.049 meters
So, the amplitude of the wave is 0.049 meters.