Tenemos un Cable de cobre de 1 km de longitud cuya sección es de 2 milímetros al cuadrado y queremos saber la resistencia que se
1 answer:
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Answer:
2.38732 rpm
1.22625 rad/s²
163.292°
Explanation:
g = Acceleration due to gravity = 9.81 m/s²
a = Acceleration =
d = Diameter of wheel = 2 m
r = Radius of wheel =
v = Speed of elevator = 25 cm/s
Angular speed is given by
The angular speed of the wheel is 2.38732 rpm
Angular acceleration is given by
The angular acceleration of the wheel is 1.22625 rad/s²
Angular displacement is given by
The angle the disk turned when it has raised the elevator is 163.292°
Answer:
T₂ = 1937.68 N
Explanation:
First, we will calculate the weight of the object:
Now, we will calculate the resultant tension in the ropes. Since the ropes are perpendicular. Therefore,
where,
T = Resultant Tension
T₁ = Tension in rope 1
T₂ = Tension in rope 2
According to the given condition tension in the first rope is 2.2 times the tension in the second rope:
T₁ = 2.2 T₂
Therefore
Now, the weight of the object must be equal to the resultant tension for equilibrium:
<u>T₂ = 1937.68 N</u>